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Nady [450]
1 year ago
6

A traffic signal system will only operate if it receives an output signal (D=1) This only can occur if: Either (a) signal A is R

ed (i.E A=0) OR (b) signal A is Green (i.E.A=1) AND (signals B AND C are both Red) (i.E. B and C are both 0) Design a logic network for the above problem.
Computers and Technology
1 answer:
kozerog [31]1 year ago
4 0

Answer:

0

Explanation:

You might be interested in
CodeHS Python Rainforest Exercise 5.4.7: Categories
nalin [4]

Answer:

List=[['Computers','IT','Programming'],['Maths', 'Algebra', 'Geometry']]

i=0

k=0

for i in range(0,2):

   print("Category:"+List[i][0])

   for k in range(1,3):

       print("\t"+List[i][k])

   

Explanation:

The required program is as above. We have used here a multidimensional list. The 0 of each row has the category,and rest are sub categories. The program above has limitations but is good enough to explain the fundamentals required.

7 0
2 years ago
Problem 1a. Write a function named hasFinalLetter that takes two parameters 1. strList, a list of non-empty strings 2. letters,
mash [69]

Answer:

The answer is the programming in Python language has strings and characters that has to be declared in the method.

Explanation:

#method

def hasFinalLetter(strList,letters):

output = #output list

#for every string in the strList

for string in strList:

#findout the length of each string in strList

length = len(string)

#endLetter is last letter in each string

endLetter = string[length-1]

#for each letter in the letters list

for letter in letters:

#compare with endLetter

#if we found any such string

#add it to output list

if(letter == endLetter):

output.append(string)

#return the output list

return output

#TestCase 1 that will lead to return empty list

strList1 = ["user","expert","login","compile","Execute","stock"]

letters1 = ["a","b","y"]

print hasFinalLetter(strList1,letters1)

#TestCse2

strList2 = ["user","expert","login","compile","Execute","stock"]

letters2 = ["g","t","y"]

print hasFinalLetter(strList2,letters2)

#TestCase3

strList3 = ["user","expert","login","compile","Execute","stock"]

letters3 = ["k","e","n","t"]

print hasFinalLetter(strList3,letters3)

8 0
2 years ago
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
sdas [7]

Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

paint_needed = area/350.0

print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

<em>import math</em>

<em> paint_colors = {'red': 35,'blue': 25,'green': 23} </em>

<em>wall_height = int(input('Enter wall height (feet):\n')) </em>

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

3 0
1 year ago
Implement a function printWordsLines() that takes as a parameter the name of an input file. It opens the input file and then pri
Talja [164]

Answer:

def printWordsLines(filename):

   file = open(filename, 'r')

   lines = 0

   words = 0

   for line in file:

       line.rstrip()

       lines += 1

       word = line.split(' ')

       words += len(word)

   print('the file ',filename,' contains ',words,' and ', lines, ' lines')

   file.close()

printWordsLines('words')

Explanation:

the file used was words in txt format and its contents are given as follows

hello aamir jan khan

parallelogram abdullah

anaconda ali

pycharm notebook

7 0
2 years ago
In this assignment you'll write a program that encrypts the alphabetic letters in a file using the Vigenère cipher. Your program
solniwko [45]

Answer:

C code is given below

Explanation:

// Vigenere cipher

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

/**

* Reading key file.

*/

char *readFile(char *fileName) {

   FILE *file = fopen(fileName, "r");

   char *code;

   size_t n = 0;

   int c;

   if (file == NULL) return NULL; //could not open file

   code = (char *)malloc(513);

   while ((c = fgetc(file)) != EOF) {

      if( !isalpha(c) )

          continue;

      if( isupper(c) )

          c = tolower(c);

      code[n++] = (char)c;

   }

   code[n] = '\0';

  fclose(file);

   return code;

}

int main(int argc, char ** argv){  

   // Check if correct # of arguments given

   if (argc != 3) {

       printf("Wrong number of arguments. Please try again.\n");

       return 1;

   }

 

  // try to read the key file

  char *key = readFile(argv[1]);

  if( !key ) {

      printf( "Invalid file %s\n", argv[1] );

      return 1;

  }

 

  char *data = readFile(argv[2]);

  if( !data ) {

      printf("Invalid file %s\n", argv[2] );

      return 1;

  }

 

   // Store key as string and get length

   int kLen = strlen(key);

  int dataLen = strlen( data );

 

  printf("%s\n", key );

  printf("%s\n", data );

 

  int paddingLength = dataLen % kLen;

  if( kLen > dataLen ) {

      paddingLength = kLen - dataLen;

  }

  for( int i = 0; i < paddingLength && dataLen + paddingLength <= 512; i++ ) {

      data[ dataLen + i ] = 'x';

  }

 

  dataLen += paddingLength;

 

   // Loop through text

   for (int i = 0, j = 0, n = dataLen; i < n; i++) {          

       // Get key for this letter

       int letterKey = tolower(key[j % kLen]) - 'a';

     

       // Keep case of letter

       if (isupper(data[i])) {

           // Get modulo number and add to appropriate case

           printf("%c", 'A' + (data[i] - 'A' + letterKey) % 26);

         

           // Only increment j when used

           j++;

       }

       else if (islower(data[i])) {

           printf("%c", 'a' + (data[i] - 'a' + letterKey) % 26);

           j++;

       }

       else {

           // return unchanged

           printf("%c", data[i]);

       }

      if( (i+1) % 80 == 0 ) {

          printf("\n");

      }

   }

 

   printf("\n");

 

   return 0;

}

4 0
2 years ago
Read 2 more answers
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