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fgiga [73]
2 years ago
6

A chemistry professor who teaches a large lecture class surveys his students who attend his class about how he can make the clas

s more interesting, hoping he can get more students to attend. The survey is optional and will be available online. Students will remain anonymous. Which of the following is the most relevant source of bias?
a. None of these.
b. Voluntary Response Bias
c. Loaded Questions
d. Perceived Lack of Anonymity
e. Response Bias
Mathematics
1 answer:
Iteru [2.4K]2 years ago
7 0

Answer:

a.

Step-by-step explanation:

I believe it's Voluntary Response Bias

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If CX = 5 units, then DZ = ___ units
gulaghasi [49]

Answer:

DZ=4\ units

Step-by-step explanation:

we know that

If CD is parallel to XZ

then

Triangle XYZ is similar to Triangle YCD

therefore

The ratio of their corresponding sides are equal

\frac{XY}{CY}=\frac{ZY}{YD}

we have

CX=5\ units, CY=25\ units, YD=20\ units,

XY=CX+CY

XY=5+25=30\ units

ZY=YD+DZ

ZY=20+DZ

substitute the values

\frac{30}{25}=\frac{20+DZ}{20}

20\frac{30}{25}={20+DZ}

24={20+DZ}

DZ=4\ units

5 0
2 years ago
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Ben has 400 counters in a bag. He gives 35 of the counters to Sonia 130 of the counters to Phil 75 of the counters to Lance What
aniked [119]

Answer:

2/5

Step-by-step explanation:

subtract 130,35,and 74 from 400 you will have 160/400 left then you find the greatest common and divide! and get 2/5

8 0
2 years ago
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Why is sin(20) = sin(160) = -sin(200) = -sin(340)?
AveGali [126]
Because they're all the same distance from the x axis on a coordinate plane. Also, remember that in quadrant I, all trig values are positive. In Q II, only sine and cosecant are positive. In Q III, only tangent and cotangent are positive. In Q IV, only cosine and secant are positive. Think of it as <u>A</u>ll <u>S</u>tudents <u>T</u>ake <u>C</u>alculus.
6 0
2 years ago
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This is suppose to be a mathematical function I need to enter into excel. "Enter a formula in cell B10 to return a value of 3500
sesenic [268]
The syntax for the IF statement is as follows:
=IF(condition, value if true, value if false)

therefore, we can enter the information from the problem:

=IF($B$9>=470000,35000,1000)

7 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
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