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1 year ago

The third graders at Grace Hardeman Elementary want to play kickball. There are 20 students, and each team will have 5 students.

Mathematics

1 answer:

Julli [10]1 year ago

5 0

Answer:

Step-by-step explanation:

If there are 20 students, and each team has 5 students, then there will be 4 teams of third graders that will play kickball.

20/5 = 4

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What is the cube root of -729a9b6

Harman [31]

<u>ANSWER</u>

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

<u>EXPLANATION</u>

We want to find the cube root of

$- 729 {a}^{9} {b}^{6}$

We express this symbolically as:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} }$

The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

${x}^{ \frac{m}{n} } = \sqrt[n]{ {x}^{m} }$

Applying this rule gives us:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} } = ({- 729 {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3} {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

Recall that

$({a}^{m} )^{n} = {a}^{mn}$

We apply this rule on the RHS to get,

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3 \times { \frac{1}{3} } } {a}^{9 \times { \frac{1}{3} } } {b}^{6 \times { \frac{1}{3} } }})$

This simplifies to

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

3 0

2 years ago

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Membership to a racket ball club has an application fee and a monthly fee that can be modeled by the function c(m) = 12.50m + 49

Ghella [55]

Answer: the last one

Step-by-step explanation:

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2 years ago

If it took Mark 45 minutes to get to work and 35 minutes to get home, how long did he spend travelling to and from work?

oksano4ka [1.4K]

Mark spent a total of 80 minutes or 1 hour and 20 minutes traveling to and from work.

45 minutes + 35 minutes = 80 minutes

There are 60 minutes per hour, so their would 1 hour and 20 minutes.

4 0

2 years ago

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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : $8d^5-3c^3d^2+5c^2d^3-4cd^4+9$

One of the polynomial which are added up is : $2d^5-c^3d^2+8cd^4+1$

Let the other polynomial be 'x'

According to the question:

$8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)$

$x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)$

Solving the like terms in above equation we get:

$x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)$

$x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8$

Hence, the correct option is A.

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2 years ago

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A family of five recently replaced its 5-gallon-per-minute showerheads with water-saving 2-gallon-per-minute showerheads. Each m

kykrilka [37]

Answer:

Family will save 3600 gallons of water by replacing the shower-heads.

Step-by-step explanation:

Number of family members in a family = 5

Each member of the family averages shower per day = 8 minutes

Total time for shower = 5×8 = 40 minutes

With a 5 gallon shower-heads each member will use water in a day = 5×40 = 200 gallons

Water consumption in 30 days = 200×30 = 6000 gallons per month

After replacing the shower-heads with 2 gallons per minute shower-heads family will use the amount of water = 40×2= 80 gallons per day

Water used in one month = 80×30 = 2400 gallons

Now water save by the family in 30-day period = 6000 - 2400 = 3600 gallons

Therefore, family will use 3600 gallons less water by replacing the water saving water heads.

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2 years ago