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1 year ago

The third graders at Grace Hardeman Elementary want to play kickball. There are 20 students, and each team will have 5 students.

Mathematics

1 answer:

Julli [10]1 year ago

5 0

Answer:

Step-by-step explanation:

If there are 20 students, and each team has 5 students, then there will be 4 teams of third graders that will play kickball.

20/5 = 4

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Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,

vazorg [7]

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

$h(t)=-16t^2+32t+48$

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

$h(t) = 48$

$h(t)=-16t^{2}+32t+48$

$48=-16t^{2}+32t+48$

$0=-16t^{2}+32t+48 - 48$

$16t^{2} - 32t = 0$

We can simplify by 16t. So

$16t(t-2)= 0$

It means that

16t = 0

t = 0

t - 2 = 0

t = 2

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

6 0

2 years ago

Jeremy analyses one of his parachute jumps.

Ulleksa [173]

Answer:

Step-by-step explanation:

8 0

2 years ago

A six foot man is standing 10 feet away from a 20 foot lamppost. what is the length of his shadow?

elena55 [62]

There are two congruent triangles that are being formed from the lamppost, the light, the ground and the man. Always try to draw a picture for these types of problems. It helps a lot when solving. Your answer should be about 4.3ft

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2 years ago

Read 2 more answers

Assume there are 365 days in a year.

MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

$\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883$

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

$\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]$

$\text{P(2 born on same day) }=1-[\frac{364}{365}]$

$\text{P(2 born on same day) }=0.002$

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0

2 years ago

Your office manager has given you a budget of $30,000 to replace the old computers in your office with new ones. Each new comput

weeeeeb [17]

1) 550 x 15 = 8250 (First you want to get the total cost of the computers)

2) 30,000 - 8250 = 21,750 (Then you want to subtract that by 30,000 to see how much money is left over)

3) 21,750/6 = 3625 (Then divide by 6 ,by the weeks, and get your answer)

Answer: $3625

7 0

2 years ago