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liberstina [14]
2 years ago
5

A group of students and workers entering a metro station were asked whether they were riding the bus or the subway. The two-way

table shows their answers.
How many people were polled?

Mathematics
2 answers:
Ostrovityanka [42]2 years ago
8 0

Answer:166 People

Step-by-step explanation:

Rufina [12.5K]2 years ago
4 0

In these types of tables, the final box, bottom rightmost, is always the main total. This total will always add up to the same number whether you add the column or the row.

Let find it for this problem.

We can get the grand total from adding the 2 number from the row or the column.

<em>If we add column, we get, 48+118=166.</em>

<em>If we add row, we get, 69+97=166.</em>

So, our total is 166. 166 people were polled.


ANSWER: 166 People

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The sum of 4 consecutive number is 330 what is the sum of the largest and the smallest number
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X + x + 1 + x + 2 + x + 3 = 330
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3 0
1 year ago
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

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New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
2 years ago
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