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Oksana_A [137]
2 years ago
11

Determine the value of base x if (211)x = (6A)16

Computers and Technology
2 answers:
Lerok [7]2 years ago
8 0
(6A)_{16}=6\cdot 16+10=106
(211)_x=2\cdot x^2+1\cdot x + 1=106
2 x^2+ x + 1-106=0
2\cdot x^2+ x -105=0
\Delta=1^2-4\cdot 2\cdot (-105)=1+840=841=29^2
x=\dfrac{-1+29}{2\cdot 2}=\dfrac{28}{4}=7

The value of base x is equal to 7.
elena-14-01-66 [18.8K]2 years ago
7 0
211x=6A•16
211x=96A
211x=96A
___. ___
211. 211

x=96A
___
211


It's hard to show fractions on here :•)
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w = [i/10.0 for i in range(0,31,1)]

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

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w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

Explanation:

List slicing (as it is called in python programming language ) is the creation of list by defining  start, stop, and step parameters.

w = [i/10.0 for i in range(0,31,1)]

The line of code above create the list w with values 0, 0.1, 0.2, . . . , 3.

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

since start, stop, and step parameters are not defined, the output returns all the list elements.

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

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the output returns the list elements from the element at index 2  to just before the second to the last element, using step size of 6.

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