Which city has a minmmum value that is lower arcadia or oakdale

You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv

Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0

2 years ago

If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t

vivado [14]

Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.

Example:
Your line is y = 4/3x + 1/3
Let's see if (0, 0) and (2, 3) belong to this line

y = 4/3·0 + 1/3 = 1/3 ≠ 0
Therefore, the line does not contain (0, 0)

y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)

6 0

2 years ago

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Harriet would like to frame her graduation picture. The picture is 8 inches wide and 11 inches long. She wants the total area of

LekaFEV [45]

Answer: i explained

Step-by-step explanation: Just do

8 times 11 = *your answer*

then

*your answer* times/subtract/divided by 108

8 0

2 years ago

There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability tha

Tpy6a [65]

Check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are:

1st.non defective, 2nd.non defective
1st.non defective, 2nd. defective
1st. defective, 2nd. non defective
1st. defective, 2nd. defective

consider the case 1st.non defective, 2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective, 2nd. defective)+P(1st. defective, 2nd. non defective)+P(1st. defective, 2nd. defective)=
0.178+0.178+0.022=0.378

Answer: 0.378

8 0

2 years ago

Determine the values of c so that the following functions represent joint probability distributions of the random variables X an

Anna11 [10]

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

7 0

2 years ago

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