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2 years ago

Which coefficient is needed in front of NaNO3 to balance the equation Na2S + Zn(NO3)2 → ZnS + _NaNO3?

Biology

2 answers:

weqwewe [10]2 years ago

8 0

I think the <span>coefficient is na2s.

</span>

Vera_Pavlovna [14]2 years ago

7 0

Coefficient is the number in front of a formula in a balanced chemical equation.

For equation to balance the number of atoms in product side must be equal to number of atoms in reactant side.

Putting coefficient 2 in front of NaNO3 balance the equation therefore the balanced equation. the answer is 2

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In fruit flies, straight wings are dominant and curly wings are recessive. What will the generations look like? Assume that Mend

anzhelika [568]

Answer:

The P generation has straight wings and curly wings.

The F1 generation has all straight wings.

The F2 generation has straight wings and curly wings.

Explanation:

This question involves a single gene coding for wing shape in fruit flies. The allele for straight wings (S) is dominant over the allele for curly wings (s). This means that allele "S" will mask the phenotypic expression of allele "s" in a heterozygous state.

According to the question, the cross follows all Mendel's method of crossing two true breeding parents with opposite traits. Hence, the parent generation (P generation) will be between a truebreeding straight wings parent (SS) and a truebreeding curly wings parent (ss). (See attached image for full cross).

Since the straight wing allele (S) is dominant, all the F1 offsprings will possess straight wings with the genotype: Ss, which is heterozygous.

If this F1 offsprings are self-crossed i.e. Ss × Ss, four possible offsprings in the phenotypic ratio 3 straight wings : 1 curly wing will be produced in the F2 generation. The offsprings will possess the following genotypes: SS, Ss, Ss, and ss.

Offsprings SS, Ss, and Ss will all be phenotypically straight-winged

Offsprings ss will be phenotypically curly-winged.

In overall, this means that P generation has both straight and curly wings (SS and ss), F1 generation has only straight wings (Ss), F2 generation has both straight and curly wings (SS, Ss and ss).

7 0

2 years ago

In order to beat, the heart needs three types of cells. describe the cells and their function.

yulyashka [42]

1. Rhythm generators (SA node)
2. Conductive cells (node cells)
3. Contractile cells (myocardial cells)

4 0

2 years ago

Genetic mutations in asexually reproducing organisms lead to more evolutionary change than do genetic mutations in sexually repr

s2008m [1.1K]

Answer:

The correct answer is b) asexually reproducing organisms, but not sexually reproducing organisms, pass all mutations to their offspring.

Explanation:

In asexually reproducing organisms all the mutation is passed to the offspring so the offspring are identical to the parents. Daughter cells contain all the genes that are present in the parent, therefore, in asexually reproducing organisms mutation leads to more evolutionary change.

In sexual reproduction, the offspring get half genes from male parents and half from female parent so a parent does not pass all the mutation in the offspring and in sexual reproduction selection pressure eliminate those offspring that have bad mutation so that the wrong mutation can not pass to next generation.

Therefore the correct answer is b.

3 0

2 years ago

In a two-point test cross, 36 of the offspring were recombinant types. The remaining 64 offspring were parental types. How many

Maksim231197 [3]

Answer:

Explanation:

A two-point test-cross is a cross between an individual with a double heterozygote genotype and a homo-zygous recessive individual in order to determine the recombination frequency between two linked genes. In genetics, one map unit (m.u.) can be defined as the measure of the distance (i.e., genetic distance instead of physical distance) between genes for which one (1) product of meiosis in one hundred (100) is recombinant. In this case, 36 of the offspring have the recombinant phenotype, while the remaining 64 offspring are not recombinant, and therefore both genes are separated by 36 mu (64 + 36 = 100 >> 36 mu).

6 0

2 years ago

Explain why the vessels that transport water in trees must be very small in diameter.

kipiarov [429]

Answer:

The diameter of the xylem vessels should be small in order for the capillary action to take place.

Explanation:

The vessels through which water is transported to different parts of the plants and trees are the xylem. Water is transported in the trees through a mechanism named as capillary action. This mechanism can occur only if the diameter of the vessels are small.

The water molecules adhere to the walls of xylem and an upward force is generated. If the diameter of the vessels i.e xylem would be small then the surface tension between the xylem and water molecules would be enough to move the water in an upward direction.

6 0

2 years ago