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Alex787 [66]
1 year ago
10

There were 567 people at a concert when a band started playing. After each song, only one-third of the people stayed to hear the

next song. How many people were left at the concert after x songs? Write a function to represent this scenario.
Mathematics
2 answers:
Harman [31]1 year ago
8 0

Answer:

For Apex the answer is f(x)=567(1/3)^x

Step-by-step explanation:


Solnce55 [7]1 year ago
7 0
To write the function correctly, it is important to assign variables correctly and understand the situation of the problem clearly. For this, we let y the number of people and x as the number of songs played.

At x = 0   y = 567
at x = 1   y = 567 - 567(1/3)
at x = 2   y = 567 - 567(1/3)(1/3)
at x = 3   y = 567 - 567(1/3)(1/3)(1/3)

Therefore, the number of people left after x songs would be represented by the equation:

y = 567 - 567(1/3)x
y = 567 ( 1- x/3 )
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4 0
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The perimeter of a rectangle is 13cm and its width is 11/4. find its length.
enyata [817]
Perimeter = 2 length + 2 width

P = 2(l) + 2(11/4)

13 = 2l +2* \frac{11}{4}

13 = 2l + \frac{2}{1} * \frac{11}{4}

13 = 2l + \frac{22}{4}     (subtract 22/4 from each side)

13 -\frac{22}{4} = 2l

13 -\frac{11}{2} = 2l

\frac{26}{2}  -\frac{11}{2} = 2l

\frac{15}{2}} = 2l

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7.5 ÷ 2 = l

3.75 = l

The answer is 3.75 or 3 \frac{3}{4}


6 0
2 years ago
The lateral surface area is _ square inches
lidiya [134]

Answer:

180

Step-by-step explanation:

3 0
1 year ago
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Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0
2 years ago
Suppose Primo Pizza's profit on a given day is always the same as the profit of Pizza Supreme's profit 3 days later. Write a fun
Andru [333]

Complete Question

Each summer Primo Pizza and Pizza Supreme compete to see who has the larger summer profit.

Let p(x) represent Primo Pizza's profit (in dollars) x days after June 1. Let s(x) represent Pizza Supreme's profit (in dollars) x days after June 1.

Suppose Primo Pizza's profit each day is 1.9 times as large as the profit of Pizza Supreme.

Write a function formula for p using the function s

Answer:

The function formula for p using the function s is p(x) = 1.9s(x)

Step-by-step explanation:

Given

p(x) = Primo Pizza's profit (in dollars) x days after June 1.

s(x) = Pizza Supreme's profit (in dollars) x days after June 1.

It is given that Primo Pizza's profit each day is 1.9 times as large as the profit of Pizza Supreme.

This implies that

p(x) = 1.9*s(x)

So, p(x) = 1.9s(x)

Hence, the function formula for p using the function s is p(x) = 1.9s(x)

6 0
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