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Citrus2011 [14]
2 years ago
7

How could you insert a new row between rows 20 and 21?

Computers and Technology
2 answers:
love history [14]2 years ago
6 0
<span>The Answer is C. Right-click row 21's row number, and then click Insert.

</span>
Natalka [10]2 years ago
3 0

If you want to add a new row in Microsoft Excel, you need to use the Insert Row function. However, if you want your row to be placed between two existing rows, the option you should choose is (C) Right-click row 21's row number, and then click Insert. If you right-click on row 20 instead, the new row would appear between row 19 and 20.

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Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0
2 years ago
In this lab, you use the pseudocode in figure below to add code to a partially created Python program. When completed, college a
Elza [17]

Answer:

Python code is given below with appropriate comments

Explanation:

#Prompt the user to enter the test score and class rank.

testScore = input()

classRank = input()

#Convert test score and class rank to the integer values.

testScore = int(testScore)

classRank = int(classRank)

#If the test score is greater than or equal to 90.

if(testScore >= 90):

   #If the class rank is greater than or equal to 25,

   #then print accept message.

   if(classRank >= 25):

       print("Accept")

   

   #Otherwise, display reject message.

   else:

       print("Reject")

#Otherwise,

else:

   #If the test score is greater than or equal to 80.

   if(testScore >= 80):

       #If class rank is greater than or equal to 50,

       #then display accept message.

       if(classRank >= 50):

           print("Accept")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

   

   #Otherwise,

   else:

       #If the test score is greater than or equal to

       #70.

       if(testScore >= 70):

           #If the class rank is greater than or equal

           #to 75, then display accept message.

           if(classRank >= 75):

               print("Accept")

           

           #Otherwise, display reject message.

           else:

               print("Reject")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

4 0
2 years ago
When handling project scope creep, which are two things that all parties involved need to be aware of?
WARRIOR [948]

Additional resource needed for the projects

Additional time needed for the project

<u>Explanation:</u>

In any project handing their will expected diversion and add on requirement, so to complete a project additional time and additional resource is required to finish a project.

As advice due the project details, end user has keep enough buffer for deviations on resource of man power and additional times taken to finish the project.

While design the project each scope of work is measure with additional time to complete the task

Each scope of work is considered as task in project management.

3 0
2 years ago
A(n) key is the set of steps used to convert an unencrypted message into an encrypted sequence of bits that represent the messag
a_sh-v [17]

Answer:

Algorithm

Explanation:

Algorithm is a set of instructions designed to perform a specific task, an independent sequence of actions to be perform to solve a problem and instruction for performing a computation.

Algorithm is A(n) key set of steps used to convert an unencrypted message into an encrypted sequence of bits that represent the message; it sometimes refers to the programs that enable the cryptographic processes.

5 0
2 years ago
Read 2 more answers
You have implemented a network where hosts are assigned specific roles, such as for file sharing and printing. Other hosts acces
yulyashka [42]

<u>Client-server</u> implemented a network where hosts are assigned specific roles, such as for file sharing and printing. Other hosts access those resources but do not host services of their own.

<u>Explanation:</u>

The client-server can be utilized on the web just as on a neighborhood (LAN). Instances of customer server frameworks on the web incorporate internet browsers and web servers, FTP customers and servers, and the DNS. Different hosts get to those assets yet don't have administrations of their own. Since it permits arrange permits numerous PCs/gadgets to interface with each other and offer assets.

5 0
2 years ago
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