Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
The time of a commercial airplane is
t+140=140+140=280 minutes
Answer:
40 and 20
Step-by-step explanation:
Gallons per day.......gallons / day.....so u put the gallons over the number of days, then divide
(1/2) / 6 = 1/2 * 1/6 = 1/12 of a gallon per day <==
Answer:
-14/15-1/15v
Step-by-step explanation:
First you make all of the fractions have the common denominator 15.
And then you have -18/15-6/15v+4/15+5/15v
Then you combine like terms to get -14/15-1/15v
= 10