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Aloiza [94]
1 year ago
5

What is the future value of $1,500 after 5 years if the appropriate interest rate is 6%, compounded semiannually?

Business
1 answer:
kap26 [50]1 year ago
5 0
Hi there
The formula is
A=p (1+r/k)^kt
A future value?
P present value 1500
R interest rate 0.06
K compounded semiannual 2
T time 5 years
So
A=1,500×(1+0.06÷2)^(2×5)
A=2,015.87

Good luck
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What is the maximum amount you would pay for an asset that generates an income of $ 250,000 at the end of each of five years if
Galina-37 [17]

Answer:

170,146

Explanation:

$250,000 / (1.08)5= 170,146

3 0
1 year ago
Geoff hesitated as he read the fast food menu, unsure whether he should supersize his order of delicious golden French fries. Do
erma4kov [3.2K]

Answer:

Geoff's target service level is 0.76

Explanation:

Doing so would expand his expense from $0.99 to $1.59 and could very well give him the sustenance he expected to endure the second 50% of his day at the workplace. Obviously, in the event that he completed his cheeseburger and the typical measure of fries, he would essentially discard the additional ones. In any case, on the off chance that he neglected to supersize his request, he would need to take a confection break mid-evening and they weren't actually offering them away in the reprieve room candy machines. He would probably require two pieces of candy, which sold for $0.95 each.

5 0
1 year ago
Read 2 more answers
An appliance dealer must decide how many (if any) new microwave ovens to order for next month. The ovens cost $220 and sell for
Vlada [557]

Answer:

Explanation:

Order 0: we have unsold items for which the return is -25

return is -25*(.4*1+.2*2+.1*3) = -25*1.1 = $-27.50

Order 1: we have to sell at a discount if no orders, otherwise sell 1, and unsold items if demand 2 or 3

return is .3*(1/2*300-220) + (1-.3)*(300-220) + -.25*(.2*1+.1*2) = .3*-70+.7*80+-25*(.4) =

-21 + 56 - 10 = $25

Order 2: we have to sell at a discount if 0 or 1 orders, sell 1 or 2, and unsold items if demand 3

return is (.3*2+.4*1)*(1/2*300-220)+(.4*1+(.2+.1)*2)*(300-220)+-25*.1 =1*-70+1*80-25*.1 =

-70 + 80 - 2.5 = $7.50

Order 3:

return is (.3*3+.4*2+.2*1)*(1/2*300-220)+(.4*1+.2*2+.1*3)*(300-220) = 1.9*-70 + 1.1*80 =

-133 + 88 = -$45

Order 1, with a return of $25, as this is the highest return.

b) If we had a perfect information, we would never pay a penalty for underordering or suffer a discounted return from over-ordering

(.4*1+.2*2+.1*3)*(300-220) = 1.1*80 = $88

Then, the value of perfect information is $88 - $25 = $63

c) P(D=0|F) = P(F|D=0)*P(D=0)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.1*.3/(.1*.3+.2*.4+.3*.2+.9*.1)=.03/.26 = 3/26

P(D=1|F) = P(F|D=1)*P(D=1)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.2.4/(.1*.3+.2*.4+.3*.2+.9*.1)=.08/.26 = 4/13

P(D=2|F) = P(F|D=2)*P(D=2)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.3*.2/(.1*.3+.2*.4+.3*.2+.9*.1)=.06/.26 = 3/13

P(D=3|F) = P(F|D=3)*P(D=3)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.9*.1/(.1*.3+.2*.4+.3*.2+.9*.1)=.09/.26 = 9/26

P(D=0|U) = P(U|D=0)*P(0)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.8*.3/(.8*.3+.3*.4+.1*.2+.1*.1)=.24/.39 = 8/13

P(D=1|U) = P(U|D=1)*P(1)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.3*.4/(.8*.3+.3*.4+.1*.2+.1*.1)=.12/.39 = 4/13

P(D=2|U) = P(U|D=`)*P(`)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.2/(.8*.3+.3*.4+.1*.2+.1*.1)=.02/.39 = 2/39

P(D=3|U) = P(U|D=3)*P(3)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.1/(.8*.3+.3*.4+.1*.2+.1*.1)=.01/.39 = 1/39

P(N|D=0 = 1-.1-.8 = .1

P(N|D=1) = 1 - .2 - .3 = .5

P(N|D=2) = 1 - .3 - .1 = .6

P(N|D=3) = 1 - .9 - .1 = 0

P(D=0|N) = P(N|D=0)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))=.1*.3/(.1*.3+.5*.4+.6*.2+.0*.1)= .03/.35 = 3/35

P(D=1|N) = P(N|D=1)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .5*.4/(.1*.3+.5*.4+.6*.2+.0*.1)= .20/.35 = 4/7

P(D=2|N) = P(N|D=2)*P(D=2)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .6*.2/(.1*.3+.5*.4+.6*.2+.0*.1)= .12/.35 = 12/35

P(D=3|N) = 0

If the result of the survey is an F, we have

P(D=0|F) = 3/26

P(D=1|F) = 4/13

P(D=2|F) = 3/13

P(D=3|F) = 9/26

If the order is 0, the return is -25*(1*4/13+2*3/13+3*9/26) = -25*47/26 = -1175/26 = -$45.19

If the order is 1, the return is 3/26*-70+(1-3/26)*80+-25*(1*3/13+2*9/26) = 515/13 = $39.62

If the order is 2, the return is (3/26*2+4/13)*-70+(1*4/13+2*(3/13+9/26))*80 + -25*9/26 =

1835/26 = $70.58

If the order is 3, the return is (3/26*3+4/13*2+3/13)*-70+(1*4/13+2*3/13+3*9/26)*80 =

795/13 = $61.15

We should order 2.

P(D=0|U) = 8/13

P(D=1|U) = 4/13

P(D=2|U) = 2/39

P(D=3|U) = 1/39

If we order 0, the return is (4/13*1+2/39*2+1/39*3)*-25 = -475/39 = -$12.18

If the order is 1, the return is 8/13*-70+(1-8/13)*80+-25*(1*2/39+2*1/39) =-580/39= -14.87

If the order is 2, the return is (8/13*2+4/13)*-70+(1*4/13+2*(2/39+1/39))*80 + -25*1/39 =

-2785/39= -$71.41

If the order is 3, the return is (8/13*3+4/13*2+2/39*1)*-70+(1*4/13+2*2/39+3*1/39)*80 =

-1780/13 = -$136.92

Order 0

P(D=0|N) = 3/35

P(D=1|N) = 4/7

P(D=2|N) = 12/35

P(D=3|N) = 0

If we order 0, the return is (4/7*1+12/35*2)*-25 = -220/7 = -$31.43

If the order is 1, the return is 3/35*-70+(1-3/35)*80+-25*(1*12/35) = 410/7 = $58.57

If the order is 2, the return is (3/35*2+4/7)*-70+(1*4/7+2*12/35)*80 = 340/7 = $48.57

We don't order 3, as the probability of 3 is 0

we order 1

We order 2 if there is an F, 0 if there is an N, and 1 if there is a U.

d) P(F) = .26

P(N) = .39

P(U) = .35

Then, the expected return is .26*1835/26 +-475/39*.39 + 410/7*.35 = $34.10

Since we make $25 if we just take 1, we should pay up to $34.10-$25 = $9.10 for the survey.

5 0
2 years ago
When business improved, Tasha Lind determined that the company had a talent shortage. Which of the following methods should she
Len [333]

Answer:

c. Outsource to a third party

Explanation:

At that time when business improved, Tasha Lind saw that the company is suffering with shortage of talent. From the given following methods she should use <u>outsource to a third party</u> for managing the shortage of talent because as outsource to a third party generally means that the company will give the contract of their work to any third party they wish. As company is suffering with shortage of talent, so the company will have to give contract to any other third party because company will not make its loss.

7 0
1 year ago
A firm pays Pam $40 per hour to assemble personal computers. Each day, Pam can assemble 4 computers if she works 1 hour, 7 compu
kherson [118]

Answer:

$1,840

Explanation:

In order to calculate the Marginal cost of producing the computers in 2nd hour of work, we need to add the marginal cost of computer and marginal cost of wage in the 2nd hour of work.

MC = MC(computers) + MC(wage)

MC = $1,800(w) + $40

MC = $1,840

Working

MC (computers ) = 3 x 600$ = $1,800

                hour        computers assembled

                    1st                        4

                    2nd                      7

If pam works 2 hours she can assemble 7 computers but she already assembled 4 computers in 1st hour.

So the 2nd-hour computers will be 3 ( 7 - 4) computers.

4 0
1 year ago
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