Answer:
A. The number of cells that are dying is balanced by the number of new cells that are being formed.
C. Harmful waste products may be accumulating.
D. The cells are likely running out of nutrients.
Explanation:
During the stationary phase, the number of viable cells remains constant. This may be due to a balance between cell division and cell death wherein the total number of newly formed cells and the cells undergoing death are equal.
Nutrient limitation is one of the several factors that make the microbial cells to enter the stationary phase. Depletion of nutrients slows down the population growth.
Accumulation of toxic waste products as it occurs during the growth of anaerobic bacteria also adversely affects the population growth.
For example, the accumulation of lactic acid and other organic acids (by-products of anaerobic respiration) inhibits the growth of the population by making the medium acidic.
Answer
1. The writing utensil’s placement facilitates the drawing of two or more lines with a single stroke of the pantograph. This means while drawing an image two or more copies of varying sizes may be created at the same time. The pantograph mirror is used to extend or retract an image.
2. The operation of a pantograph relates to dilations and similarity in that both of the processes are done on the graph and it is possible to use similar triangles through measuring the size of the triangles. Pantograph contains links that maybe arranged in other ways because they contain a parallelogram.
3. You can use similar triangles to describe the working of the pantograph because the ratio of similitude is set when determining where to put the pin. When one triangle is moved with the part being specific to the point (tracing style), along the outline of the image, an enlarged/reduced version of the image is created by movement of the other triangle (drawing stylus point).
4. Pantograph has been replaced by modern ways of producing duplicates such as photocopying, mass printing and digital filing. This is because the technique is currently outdated and the fact that it is difficult to use then now due to their complex designs which does not allow users to properly grip an actual writing utensil like the pen.
Answer: The correct answer is- C) vacuole.
Large central Vacuole is a specialized fluid filled organelle, present only in plant cell. It is primarily involved in providing support and shape to the plant cell by maintaining the turgor pressure ( a hydrostatic force that is produced due to the cell contents against the inner side of the cell wall). The central vacuole stores water ( that flows through osmosis) and maintains turgor pressure in a plant cell.
Turgor pressure provides mechanical support and helps in the growth and development of plant.
Answer:
The gray matter in the spinal cord is located in the <u><em>grey column</em></u> , and its shape resembles a letter H, or a butterfly. The cell bodies of somatic motor neurons are primarily housed in the <u><em>ventral or anterior</em></u> horns, which innervate skeletal muscle.
Explanation:
The grey matter is a component of the central nervous system that contains neuronal and glial cells and it can be found in the brain, brainstem and <em>spinal cord, in this last one, is found in the grey column, a mass of grey matter shaped in H form.</em>
In this column the grey matter is divided into four columns (as you can see in the image I added):
- The dorsal or posterior horn: contains somatosensorial neurons
- <em> The ventral or anterior horn: contains somatic efferent motor neurons (they exit the spinal cord to innervate skeletal muscle) </em>
- The intermediate column: contains neurons to innervate visceral organs
- The lateral horn: same as the intermediate column
I hope you find this information useful and interesting! Good luck!
Answer:
0.2404
Explanation:
The genes R/r and E/e are linked and there is 4% recombination between them.
<u>The possible genotypes and phenotypes are:</u>
- RR or Rr: Rh+ blood type
- rr: Rh- blood type
- EE or Ee: elliptocytosis
- ee: normal red blood cells
Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).
Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele from his father, so he has the genotype eR/Er.
Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.
The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).
<u />
<u>Tom will produce the following gametes:</u>
- eR, parental (0.48)
- Er, parental (0.48)
- er, recombinant (0.02)
- ER (recombinant (0.02)
<u>Terri will produce the following gametes:</u>
- ER, parental (0.48)
- er, parental (0.48)
- Er, recombinant (0.02)
- eR, recombinant (0.02)
A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:
- Er (0.48) × er (0.48) = 0.2304 Er/er
- Er (0.48) × Er (0.02) = 0.0096 Er/Er
- er (0.02) × Er (0.02) = 0.0004 er/Er
And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404
