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daser333 [38]
2 years ago
10

Explain the error in the work shown. Find the correct answer.

Mathematics
2 answers:
const2013 [10]2 years ago
5 0
You cant have a negative exponent

Kobotan [32]2 years ago
4 0
The mistake is in 3rd step, as we can't equate powers if bases are different.
4^-3=2^8a
2^-6=2^8a
-6=8a
-3/4=a
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Find the GCF of monomials 34s^2t and 96st^2
andrey2020 [161]

Answer:

Down below

Step-by-step explanation:

3264s^{3}   t^{3}

6 0
2 years ago
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is___ units. The point (
Pachacha [2.7K]
<span>A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is 5_ units. The points(-7,5) and (-7,-1</span>) lie on this circle.
3 0
2 years ago
Read 2 more answers
At a particular restaurant, each mini hotdog has 80 calories and each pizza roll has 50 calories. A combination meal with mini h
cestrela7 [59]

There are 15 mini hotdogs and 5 mini pizza rolls in the combination meal.

Step-by-step explanation:

Given,

Calories in each hotdog = 80 calories

Calories in each mini pizza = 50 calories

Combined meal = 20

Combined calories = 1450 calories

Let,

x represent the number of hot dogs.

y represent the number of mini pizzas.

According to given statement;

x+y=20     Eqn 1

80x+50y=1450    Eqn 2

Multiplying Eqn 1 by 80

80(x+y=20)\\80x+80y=1600\ \ \ Eqn\ 3

Subtracting Eqn 2 from Eqn 3

(80x+80y)-(80x+50y)=1600-1450\\80x+80y-80x-50y=150\\30y=150

Dividing both sides by 30

\frac{30y}{30}=\frac{150}{30}\\y=5

Putting y=5 in Eqn 1

x+5=20\\x=20-5\\x=15

There are 15 mini hotdogs and 5 mini pizza rolls in the combination meal.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10546617
  • brainly.com/question/10552347

#LearnwithBrainly

7 0
2 years ago
Employees in the marketing department of a large regional restaurant chain are researching the amount of money that households i
kap26 [50]

Answer:

The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34              45 to 54

  1329                    2268

  1906                    1965

 2426                     1149

  1826                     1591

  1239                    1682

   1514                     1851

  1937                     1367

  1454                    2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01

Compute the <em>z</em>-score for the group "25 to 34" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37

Compute the mean and standard deviation for the group "45 to 54" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39

Compute the <em>z</em>-score for the group "45 to 54" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25

Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

8 0
2 years ago
How do you Evaluate 3f(2)
kondor19780726 [428]

IT IS TWELVE............ 12

4 0
2 years ago
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