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Law Incorporation [45]
2 years ago
8

An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the fun

ctions over the interval
a.The exponential grows at half the rate of the quadratic.
b.The exponential grows at the same rate as the quadratic.
c.The exponential grows at twice the rate of the quadratic.
d.The exponential grows at four times the rate of the quadratic.

Mathematics
2 answers:
Sindrei [870]2 years ago
8 0

Just took the test and the answer is a.

aleksley [76]2 years ago
3 0
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.

The rate of change of a function f(x) over an interval
a \leq x \leq b
is given by
\frac{f(b)-f(a)}{b-a}

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
0 \leq x \leq 1
is given by
\frac{f(1)-f(0)}{1-0} = \frac{2-1}{1} =1

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
0 \leq x \leq 1
is given by
\frac{g(1)-g(0)}{1-0} = \frac{1-0}{1} =1

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>0 \leq x \leq 1.</span>
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If the farmer has 234 feet of fencing, what are the dimensions of the region which enclose the maximal area?
marissa [1.9K]

Answer: 58 ft × 58 ft  

Step-by-step explanation:

Let the length of the region = x feet

And, the width of the region = y feet

Since, the perimeter of the region = 234 feet ( Given )

⇒ 2(x+y) = 234

⇒ x+y = 117

⇒ y = 117 - x

Again the area of the region, A = xy

⇒ A(x) = x(117-x)

⇒ A(x) = 117x - x^2

By differentiating the above equation with respect to x,

⇒ A'(x) = 117 - 2x  

For maxima or minima,

A'(x) = 0

\implies 117 - 2x = 0

\implies -2x = -117

\implies x = 58.5

Again differentiating equation A'(x) with respect to x,

We get, A''(x) = -2

Hence, For x = 58.5 A''(x) = negative

⇒ For x = 58.5 feet the area A(x) is maximum,

⇒ The length of the region having maximum area = x = 58.5 feet

And, the width of the region having maximum area = y = 117-x= 117 - 58.5=58.5 feet,

⇒ The dimension of the region having the maximum area = 58.5 ft × 58.5 ft

8 0
2 years ago
Read 2 more answers
A standard city block in Manhattan is a rectangle measuring 80 m by 270 m. A resident wants to get from one corner of a block to
kondor19780726 [428]

Answer:

68.4 meters shorter

Step-by-step explanation:

ok so you want to compare the distance  80 m + 270 m with the diagonal length.

the diagonal length =  root ( 80^2   +  270^2 )

diagonal length = root(6400 +  72900)

diagonal = root(79300) =281.602 m

so.

350 - 281.602 = 68.397 meters  about  68.4 meters  shorter than walking around

5 0
2 years ago
Find the geometric mean of 16 and 25. Round your answer to the nearest tenth
romanna [79]

Answer:

20

Step-by-step explanation:

5 0
2 years ago
The expression below is the factorization of what trinomial? -1(x+7)(x-4)
vekshin1
The answer is (-x^2 - 3x +28)
3 0
2 years ago
Read 2 more answers
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
Stella [2.4K]

Answer:

x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

0=-3x^{2}-2x+6  

so

a=-3\\b=-2\\c=6

substitute in the formula

x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(-3)(6)}} {2(-3)}

therefore

x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

4 0
2 years ago
Read 2 more answers
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