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Oksana_A [137]
2 years ago
4

When this character is used in a search text, the search engine uses it as a placeholder for any possible word?

Computers and Technology
1 answer:
aalyn [17]2 years ago
3 0
There are no placeholder signs (for Google). Usually you just skip the word and the engine corrects it.
You might be interested in
Write a program that replaces words in a sentence. The input begins with word replacement pairs (original and replacement). The
marin [14]

Answer:

Following are the program in the Python Programming Language

#set variable to input sentence to replace words

sen = input()

#split that sentence

sen = sen.split()

#set variable to input whole sentence

get = input()

#set the for loop to replace words

for i in range(0, len(sen), 2):

 #check condition when words of sen is in get

 if sen[i] in get:

   #then, replace words

   get = get.replace(sen[i], sen[i+1])

#print the whole string after replacing

print('\n',get)

Explanation:

<u>Following are the description of the program</u>.

  • Set a variable 'sen' that get a sentence for replacing the word.
  • Split that sentence by split() method and again store that sentence in the following variable.
  • Set a variable 'get' that gets the whole sentence from the user.
  • Set the for loop for replacing words then, set the if conditional statement that checks the condition that the variable 'sen' in the variable 'get' then replace the words.
  • Finally, print the whole sentence after the replacement.
4 0
2 years ago
Most ________ are accompanied by several common utility programs, including a search program, a storage management program, and
diamong [38]

Answer:

operating systems

Explanation:

The operating systems is shortly known as OS. It is a system software which manages the software resources of the computer, computer hardware and also provides some common services for the various computer programs.

Most of the operating systems available in the market provides some common utility programs such as the search program, a backup program and a storage management program also.

Some common operating systems are : Linux, Microsoft Windows, Ubuntu, macOS, Unix, and many more.

4 0
2 years ago
(NumberFormatException)Write the bin2Dec(String binaryString) method to convert a binary string into a decimal number. Implement
tresset_1 [31]

The following program will be used that prompts the user to enter a binary number as a string and displays decimal equivalent of the string.

<u>Explanation:</u>

NumberFormat.java

import java.util.Scanner;

public class NumberFormat{

public static void main(String[] args) {

      Scanner scan = new Scanner(System.in);

      try{

      System.out.println("Enter a binary string:");

      String s = scan.next();

      int integerValue = bin2Dec(Integer.parseInt(s));

      System.out.println("The decimal value of "+s+" is "+integerValue);

      }

      catch(NumberFormatException e){

          System.out.println(e);

      }

  }  

  public static int bin2Dec(int binaryNumber) throws NumberFormatException{

  int decimal = 0;

  int p = 0;

  try{

  while(true){

  if(binaryNumber == 0){

  break;

  } else {

  int temp = binaryNumber%10;

  decimal += temp*Math.pow(2, p);

  binaryNumber = binaryNumber/10;

  p++;

  }

  }

  }

  catch(NumberFormatException e){

      throw new NumberFormatException("Invalid binary number");

  }

  return decimal;

  }

}

Output:

Enter a binary string:

1011000101

The decimal value of 1011000101 is 709

5 0
2 years ago
You need to replace a broken monitor on a desktop system. You decide to replace it with a spare monitor that wasn't being used.
AysviL [449]
Firmware hope this helps!!
6 0
2 years ago
Read 2 more answers
Create the class named SortFile. The class will have a single attribute, which is an ArrayList of integers. The class will have
S_A_V [24]

Answer:

See explaination

Explanation:

//SortFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

public class SortFile {

// array list of integers to store the numbers

private ArrayList<Integer> list;

// default constructor

public SortFile() {

// initializing list

list = new ArrayList<Integer>();

// reading file name using a scanner

Scanner sc = new Scanner(System.in);

System.out.print("Enter file name: ");

String filename = sc.nextLine();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

// opening file

sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

// closing file

sc.close();

} catch (FileNotFoundException e) {

// exception occurred.

System.err.println(e);

}

}

// constructor taking a file name

public SortFile(String filename) {

// initializing list

list = new ArrayList<Integer>();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

Scanner sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

sc.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

}

// method to return a sorted array of integers containing unique elements

// from list

public int[] sort() {

// creating an array of list.size() size

int arr[] = new int[list.size()];

// count of unique (non duplicate) numbers

int count = 0;

// looping through the list

for (int i = 0; i < list.size(); i++) {

// fetching element

int element = list.get(i);

// if this element does not appear before on list, adding to arr at

// index=count and incrementing count

if (!list.subList(0, i).contains(element)) {

arr[count++] = element;

}

}

// now reducing the size of arr to count, so that there are no blank

// locations

arr = Arrays.copyOf(arr, count);

// using selection sort algorithm to sort the array

int index = 0;

// loops until index is equal to the array length. i.e the whole array

// is sorted

while (index < arr.length) {

// finding the index of biggest element in unsorted array

// initially assuming index as the index of biggest element

int index_max = index;

// looping through the unsorted part of array

for (int i = index + 1; i < arr.length; i++) {

// if current element is bigger than element at index_max,

// updating index_max

if (arr[i] > arr[index_max]) {

index_max = i;

}

}

// now we simply swap elements at index_max and index

int temp = arr[index_max];

arr[index_max] = arr[index];

arr[index] = temp;

// updating index

index++;

// now elements from 0 to index-1 are sorted. this will continue

// until whole array is sorted

}

//returning sorted array

return arr;

}

//code for test-run

public static void main(String[] args) {

//initializing SortFile using default constructor

SortFile sortFile = new SortFile();

//displaying sorted array

System.out.println(Arrays.toString(sortFile.sort()));

}

6 0
2 years ago
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