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Alexandra [31]
2 years ago
13

PowerPoint is a visual aid for many speakers. Discuss some points to remember when adding text to a PowerPoint presentation. How

do they help make the experience better for the audience and the presenter? What things can you do when creating a PowerPoint presentation to assure that your work adds to the speaker’s presentation without detracting attention from the speaker?
Computers and Technology
1 answer:
Murljashka [212]2 years ago
7 0
1. Less picture less distraction, but where to put pictures ? At the start of your presentation just to initially get the attention of the audience.
2. Use bullets for texts, never use paragraphs. Use short text or even words only which captures the subject of the presentation.
3. In conjunction with point 1. Use less animations as well. Especially for formal presentations

Additionally : Make sure to know your audience, for professionals, make the presentations short and precise. For much informal audiences you can be playful but always keep in mind not to overshadow the attention from the speaker.
You might be interested in
Do Exercise 6.4 from your textbook using recursion and the is_divisible function from Section 6.4. Your program may assume that
Reika [66]

Answer:

Here is the python method:

def is_power(n1, n2): # function that takes two positive integers n1 and n2 as arguments

   if(not n1>0 and not n2>0): #if n1 and n2 are not positive integers

       print("The number is not a positive integer so:") # print this message if n1 and n2 are negative

       return None # returns none when value of n1 and n2 is negative.

   elif n1 == n2: #first base case: if both the numbers are equal

       return True #returns True if n1=n2

   elif n2==1: #second base case: if the value of n2 is equal to 1

       return False #returns False if n2==1

   else: #recursive step

       return is_divisible(n1, n2) and is_power(n1/n2, n2) #call divisible method and is_power method recursively to determine if the number is the power of another

Explanation:

Here is the complete program.

def is_divisible(a, b):

   if a % b == 0:

       return True

   else:

       return False

def is_power(n1, n2):

   if(not n1>0 and not n2>0):

       print("The number is not a positive integer so:")  

       return None  

   elif n1 == n2:

       return True

   elif n2==1:

       return False

   else:

       return is_divisible(n1, n2) and is_power(n1/n2, n2)  

print("is_power(10, 2) returns: ", is_power(10, 2))

print("is_power(27, 3) returns: ", is_power(27, 3))

print("is_power(1, 1) returns: ", is_power(1, 1))

print("is_power(10, 1) returns: ", is_power(10, 1))

print("is_power(3, 3) returns: ", is_power(3, 3))

print("is_power(-10, -1) returns: ", is_power(-10, -1))  

The first method is is_divisible method that takes two numbers a and b as arguments. It checks whether a number a is completely divisible by number b. The % modulo operator is used to find the remainder of the division. If the remainder of the division is 0 it means that the number a is completely divisible by b otherwise it is not completely divisible. The method returns True if the result of a%b is 0 otherwise returns False.

The second method is is_power() that takes two numbers n1 and n2 as arguments. The if(not n1>0 and not n2>0) if statement checks if these numbers i.e. n1 and n2 are positive or not. If these numbers are not positive then the program prints the message: The number is not a positive integer so. After displaying this message the program returns None instead of True of False because of negative values of n1 and n2.

If the values of n1 and n2 are positive integers then the program checks its first base case: n1 == n2. Suppose the value of n1 = 1 and n2 =1 Then n1 is a  power of n2 if both of them are equal. So this returns True if both n1 and n2 are equal.

Now the program checks its second base case n2 == 1. Lets say n1 is 10 and n2 is 1 Then the function returns False because there is no positive integer that is the power of 1 except 1 itself.

Now the recursive case return is_divisible(n1, n2) and is_power(n1/n2, n2)  calls is_divisible() method and is_power method is called recursively in this statement. For example if n1 is 27 and n2 is 3 then this statement:

is_divisible(n1, n2) returns True because 27 is completely divisible by 3 i.e. 27 % 3 = 0

is_power(n1/n2,n2) is called. This method will be called recursively until the base condition is reached. You can see it has two arguments n1/n2 and n2. n1/n2 = 27/3 = 9 So this becomes is_power(9,3)

The base cases are checked. Now this else statement is again executed  return is_divisible(n1, n2) and is_power(n1/n2, n2) as none of the above base cases is evaluated to true. when is_divisible() returns True as 9 is completely divisible by 3 i.e. 9%3 =0 and is_power returns (9/3,3) which is (3,3). So this becomes is_power(3,3)

Now as value of n1 becomes 3 and value of n2 becomes 3. So the first base case elif n1 == n2: condition now evaluates to true as 3=3. So it returns True. Hence the result of this statement print("is_power(10, 2) returns: ", is_power(10, 2))  is:                                                                                                

is_power(27, 3) returns:  True

7 0
2 years ago
What is a typical grace period for a credit card...
Schach [20]
It is 20 to 25 days so c is correct
6 0
2 years ago
Read 2 more answers
3.14 LAB: Simple statistics for Python
Ad libitum [116K]

Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

8 0
2 years ago
What will be the output of the following Python code? class A: def test1(self): print(" test of A called ") class B(A): def test
Vlad [161]

Answer:

"test of B called"

Explanation:

  • The object is created for the D class, but there are two test methods in class B and C.
  • The D class does not hold any test method. So when the object called the test method. Then the B method is called.
  • It is because the B class is declared first in the inheritance of D class like in the statement "class D(B, C)".
  • If the statement will be "class D(C, B)", then the C method will be called.
  • if the D class holds the method test, then only the D method will be called.
  • Hence the output is "test of B called".
7 0
2 years ago
In this challenge, write a function to add two floating point numbers. Determine the integer floor of the sum. The floor is the
Wewaii [24]

Answer:

def floor_sum(number1, number2):

   total = number1 + number2

   if total >= 0:

       return int(total)

   else:

       return int(total) - 1

   

print(floor_sum(1.1, 3.05))

Explanation:

*The code is in Python.

Create a function called floor_sum that takes two parameters, number1 and number2

Sum them and set it to the total

Check if the total is positive number or 0, return the integer part of the total. Otherwise, subtract 1 from the integer part of the total and return it.

Call the function with given parameters in the question and print the result

Note that if the result is a negative value like -5.17, the floor of the result is -6 not -5.

5 0
2 years ago
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