Answer:
public static void main(String[] args) {
String ing[] = {"ten","fading","post","card","thunder","hinge","trailing","batting"};
for (String i: ing){
if (i.endsWith("ing")){
System.out.println(i);
}
}
}
Explanation:
The for-loop cycles through the entire list and the if-statement makes it so that the string is only printed if it ends with "ing"
<span>Shared memory buffering would work best. This would give the ports the best allocation of resources, using only those that are the most active and best allocated for the size of the frames being transmitted in the current traffic. In addition, any port can store these frames, instead of being specifically allocated as per other types of memory buffering.</span>
Answer:
O(n^2)
Explanation:
The number of elements in the array X is proportional to the algorithm E runs time:
For one element (i=1) -> O(1)
For two elements (i=2) -> O(2)
.
.
.
For n elements (i=n) -> O(n)
If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)
Answer:
15.420 dB
Explanation:
the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz is 15.420 dB.
Answer:
D) Comparative
Explanation:
Comparative report is an analytical approach to report writing, where the aim is to determine the performance or contribution of individual constituents.
