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zmey [24]
2 years ago
4

John needs to make a scale drawing of his school building for art class. If the building is 256.25 meters long, and John scales

it down using a ratio of 25 meters to 1 inch, how long will the building be in the sketch?
Mathematics
2 answers:
Ghella [55]2 years ago
8 0
The building in the sketch will be 10.25 inches long.
kondaur [170]2 years ago
3 0

Answer:

10.25 inches in the sketch

Step-by-step explanation:

Since we are talking about scales drawing, we can solve this problem using proportions, the ratio John will use is 25:1. We will write the proportion using this information and then we will solve for x.

\frac{25}{1} =\frac{256.25}{x} \\x=256.25/25\\x=10.25

Therefore, the building will be 10.25 inches in the sketch.

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ddd [48]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
Amad was curious if triangles \triangle ABC△ABCtriangle, A, B, C, and \triangle EDF△EDFtriangle, E, D, F were congruent. He was
11111nata11111 [884]

Answer:

There is no error, Amad is correct.

Step-by-step explanation:

Khan Academy Checked.

3 0
2 years ago
The 8th term of a GP is -7/32 find its common ratio if its first term is 28
Ugo [173]
<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

       \text{8}^{th} term of a Geometric progression is given as \dfrac{-7}{32}. The first term is given as 28.

       Any general Geometric progression can be represented using the series a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}.

The first term in such a GP is given by a, common ratio by r, and the n^{th} term is given by ar^{n-1}.

       In the given GP, a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}

∴ Common ratio is \dfrac{-1}{2}.

5 0
2 years ago
Greatest to least of 2/3, 0.67,5/9,0.58,7/12
Iteru [2.4K]
.67,2/3,5/9,7/12,.58
Hope this helps :D
7 0
2 years ago
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