Industrial pollution is density-independent
habitat is density-dependent
food is also density-dependent because its availability varies depending on this factor
a hurricane is abiotic and density-independent
number of mates is density-dependent and hunting by humans is density-independent
Answer:
Wound healing is a process to regenerate cells at the site of an injury or infection. Asexual reproduction is a process in which daughter cells are produced from a single cell or organism.
The wound healing process is similar to asexual reproduction because both the processes use mitosis for cell division. As a result of mitosis, two daughter cells are produced which are identical to the parent cells. Hence, during wound healing and asexual reproduction, the same cells as the parent cells are produced.
Answer:
1.2 mL
Explanation:
<em>This is a problem of simple dilution. The dilution principle simply agrees that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Recall that: number of moles = mass/molar mass or molarity x volume.
Hence, for the dilution principle:
initial molarity x initial volume = final molarity x final volume.
In this case, initial molarity of NaOH = 1 M, initial volume = ?, final molarity = 0.1 M, final volume = 12.0 mL.
Initial volume = final molarity x final volume/initial molarity
= 0.1 x 12/1 = 1.2 mL
It thus means that 1.2 mL of 1 M NaOH would be taken and then diluted up to 12.0 mL mark by the addition of distilled water in order to produce 12.0 mL, 0.10 M NaOH solution.
Answer:
Option E, Floppy ears are dominant over straight ears; coat color is determined by incomplete dominance
Explanation:
Let the allele for floppy ears be "F" and the allele for straight ears be "f"
And Let the allele for black coat color be "B" and the color for white coat color be "b"
Now, the cross is carried out between the first group having floppy ears and white coat color (FFbb) and the second group having straight ears and black coat color (ff BB)
The 16 offspring have genotype FfBb
Phenotype of 16 offspring is Floppy ears and grey coat
Ff represents the floppy ear , thus "F" is dominant over "f"
Bb represents the grey color which is a case of incomplete dominance in which none of the real trait i.e black or white is expressed.
Hence, option E is correct
Answer:
1. Cell walls: virtually all bacteria contain peptidoglycan in their cell walls; however, archaea and eukaryotes lack peptidoglycan. Various types of cell walls exist in the archaea. Therefore, the absence or presence of peptidoglycan is a distinguishing feature between the archaea and bacteria
