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MrMuchimi
2 years ago
7

A spinner number 1-10 is spun. Each number is equally likely to be spun. What is the probability of spinning: 1. an odd number O

R a power of three?
2. a number less than 8 OR a divisor of 15?
Mathematics
2 answers:
MrRissso [65]2 years ago
4 0
Each number has a 1 in 10 chance(1/10) of getting spun. There are 5 odd number and 5 even numbers, there is 1 number divisible by 3, there are 7 numbers less than 8, and to get 15 you multiply 3 by 5.
1. 5/10(1/2) or 1/10
2. 7/10 or 2/10(1/5)
yawa3891 [41]2 years ago
3 0

Answer:

B) Probability of number less than 8 OR a divisor of 15 = 1

Step-by-step explanation:

Given that the spinner number 1-10, therefore sample space = 10.

Each number is equally likely to be spun = 1/10 for each number.

A) probability of having an odd number OR a power of three?

Probability of odd number = number of odd number from 1-10 / sample space

Number of odd number = 5 {1,3,5,7,9}

Probability of odd number = 5/10 = 1/2

Probability of power of three = number of power of three from 1-10 / sample space

power of three from 1-10 = 1 (1x1x1) and 8 (2x2x2)

number of power of three from 1-10 = 2 {1,8}

Probability of power of three = 2/10

probability of having an odd number OR a power of three = probability of having an odd number + a power of three

probability of having an odd number OR a power of three = 5/10 + 2/10 = 7/10

B) probability of number less than 8 OR a divisor of 15

Number less than 8 = 7 {1,2,3,4,5,6,7}

Probability of number less than 8 = 7/10

Divisor of 15 from 1-10 = 3 {1,3,5}

Probability of divisor of 15 = 3/10

Probability of number less than 8 OR a divisor of 15 = probability of number less than 8 + a divisor of 15

Probability of number less than 8 OR a divisor of 15 = 7/10 + 3/10 = 10/10 = 1

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The question does not make sense.
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