<span>Phytochemicals
Phytochemicals are biologically active however they are non-nutrient because they are not required. But they are active biologically active in that some can be used to protect cells from oxidative damage in the form of antioxidants.</span>
answer mercury
really hope that this helps yall
Answer:
By stopping the translation process, leading to a non-functional protein.
Explanation:
The genes of organisms are the protein-coding regions of the genetic material (DNA). They are expressed in a two step process to produce functional products e.g proteins that bring about certain phenotypes in the organisms. The two stages involved in gene expression are viz: transcription and translation.
During transcription, the gene (DNA) is transcribed into RNA molecule which is read in a group of three nucleotides called CODON during translation. Translation synthesizes an amino acid from each codon. A STOP CODON i.e. UUC, UUG and UUA signals the end of the translation process and brings it to an halt.
Hence, if a mutation i.e. a change in the nucleotide sequence, causes a stop codon to be produced during the expression of Lucy's ADA gene, the stop codon will signal the end of the translation process. Because the ADA protein was truncated, it will be non-functional i.e. not work in Lucy's body.
Answer: I would say the answer is D. ( my opinion )
Correct answer: "<span>0 homozygous black (bb): 1 heterozygote (black) (bb): 1 homozygous orange "
By crossing a </span><span>heterozygous black-eyed individual (one dominant allele and one recessive allele) with a homozygous orange-eyed individual (only recessive alleles), the possible combinations of the gametes from each individual will lead to the ever presence of a recessive allele (the only one that is passed from the homozygous recessive parent) in the offspring, and either a dominant allele or a recessive allele from the heterozygous parent. So, the outcome offspring will either be heterozygous (with a dominant allele from the heterozygous parent) or homozygous recessive (with a recessive allele from the heterozygous parent). It is impossible to form homozygous dominant individuals from this crossing.
So, the resultant genotypic ratio from this crossing is 0 homozygous dominant:1 heterozygous:1 homozygous recessive.</span>
