Answer:
trocophore larva
Explanation:
The trocophore larva is a marine planktonic larvae. The mollusca, annelida, and nemerteans shows trocophore as larval stage.
The trocophore larva shows similarities with invertebrates group of organisms. This similarities provide evidence that bilateral symmetry organisms evolved from radial symmetry. The larva represents a transitional stage in ctenophore emergence. There are close similarities in trocophore larva and annelid larva (echinoderm). Thus, a close evolutionary relationship between annelids and mollusks is suggested by the presence of a <u>trocophore </u>larva in both phyla as well as by molecular sequence comparisons.
the answer is ocean currents, climate, and weather. This is the correct answer because I did it and I got it right........please mark brainliest.......tysm
Answer:
The trait is Y-linked
Explanation:
The only plausible explanation behind the inheritance pattern shown by the porcupine trait is that it is <u>Y-linked</u>.
<em><u>Y-linked traits are limited to the Y chromosome only</u></em><em>, a sex chromosome that is peculiar to only the male gender. Chromosomally, females are XX while males are XY. Hence, only the male gender has the genetic capacity to inherit the porcupine trait. This is why only the sons of Edward Lambert, and never the daughters, exhibited the trait. </em>
Answer:
The first plant demonstrate stunt growth. The second one demonstrate rapid growth
Explanation:
The first one lacks proper care and is not exposed to sunlight. The second one is the opposite of the first one
Answer:
The correct answer is 3' UCA 5'
Explanation:
The rule of pairing of base-pair says that A and T base pairs with each other with two hydrogen bonds and G and C base pairs with each other with three hydrogen bonds in DNA. In the case of RNA Uracil comes at the place of thymine that means uracil replaces thymine.
Therefore according to this base-pairing rule the corresponding codon of mRNA transcribes from DNA codon 5' AGT 3' will be 3' UCA 5' as U came in place of A nucleotide, C comes in place of G nucleotide, and A comes in place of T nucleotide.
Therefore the correct answer is 3' UCA 5'.
