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Vaselesa [24]
2 years ago
6

.04 is 1/10 of what number

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
4 0
.4. To multiply by ten, you move the decimal to the right one place



professor190 [17]2 years ago
4 0

Answer:

0.4

Step-by-step explanation:

Let x be 1/10 of 0.04.

1/10 of x would be \frac{1}{10}x.

We can represent our given information in an equation as:

\frac{1}{10}x=0.04

Let us solve for x.

10*\frac{1}{10}x=10*0.04

x=0.4

Therefore, 0.04 is 1/10 of 0.4.

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Answer:

(-3,1)

Step-by-step explanation:

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Why do you think a removable discontinuity (hole) doesn't produce an asymptote on the graph of a polynomial function, even thoug
Monica [59]
Because  removable discontituity means that the limit of the function at that point has a finite value, and then you define the value of the function as that valu (the limit value).

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2 years ago
At a restaurant, when a customer buys four pretzels the fifth pretzel is free. soft pretzels cost $3.90 each. you ordered 12 sof
elixir [45]

Answer:

($3.90)(12) - (2)($3.90) = 39.00

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Step-by-step explanation:

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1 year ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

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1 year ago
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Marat540 [252]

Answer:

Consider the function f (x) = (x +4) (x + 2).

Step-by-step explanation:

4 0
1 year ago
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