The answer is B. Hope this helps!
Answer:
n = 17
Step-by-step explanation:
Assuming
- probability of success (making free throw) does not vary
We have
n = 17 (trials)
p = 0.479
x > 9
Answer:
The length of the hypotenuse is 30 feet
Step-by-step explanation:
Here, we are to calculate the length of the hypotenuse of an iscosceles right triangle.
For the triangle to be isosceles, it means that the opposite and the adjacent are equal in length.
Now, to calculate the value of the hypotenuse, we make use of the Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Mathematically;
let’s say the hypotenuse is length h feet
h^2 = {15√(2)}^2 + {15√(2)}^2
h^2 = (225 * 2) + (225 * 2)
h^2 = 450 + 450
h^2 = 900
h = √(900)
h = 30 feet
Answer: Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.
We assume all employees are either full-time or part-time.
36 = 24 + 12
If the number of full-time employees is 24 or less, the number of part-time employees must be 12 or more. (Thinking, based on knowledge of sums.)
_____
You can write the inequality in two stages.
- First, write and solve an equation for the number of full-time employees in terms of the number of part-time employees.
- Then apply the given constraint on full-time employees. This gives an inequality you can solve for the number of part-time employees.
Let f and p represent the numbers of full-time and part-time employees, respectively.
... f + p = 36 . . . . . . given
... f = 36 - p . . . . . . . subtract p. This is our expression for f in terms of p.
... f ≤ 24 . . . . . . . . . given
... (36 -p) ≤ 24 . . . . substitute for f. Here's your inequality in p.
... 36 - 24 ≤ p . . . . add p-24
... p ≥ 12 . . . . . . . . the solution to the inequality
