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2 years ago

Explain how tapeworms can survive without a coelom, a mouth, a digestive system, or an excretory system.

1 answer:

4 0

They absorb food from their environment and release ammonia into their environment through their body surface because their body is very flat, due to the lack of coelom

Hope this helped

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Question 2(Multiple Choice Worth 4 points) (03.02 LC) In what layer are convection currents found? Continental crust Inner core

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Question 2 is ansethosphere

Question 3 is high pressure(i think)

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Sort the statements based on whether they describe DNA replication in eukaryotes or prokaryotes. Replication takes place in the

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In eukaryotes, replication takes place in the nucleus as prokaryotes do not have a true nucleus and replication takes place in the cytoplasm. The nucleus of the eukaryotes is the location where genetic material (DNA) is found; in prokaryotes, the genetic material is condensed in the cytoplasm called the nucleoid. There are multiple replication forks or multiple origins of replication in eukaryotes in contrast to prokaryotes which only has one origin of replication. Lastly, replication in eukaryotes occurs at multiple points along the chromosome; in contrast with prokaryotes where it occurs at just one point on the chromosome.

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2 years ago

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Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers tur

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Answer:

See the answer below

Explanation:

Let the disorder be represented by the allele a.

Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.

Since the four adults are carriers, their genotypes would be Aa.

Aa x Aa

Progeny: AA 2Aa aa

Probability of being affected = 1/4

Probability of being a carrier = 1/2

Probability of not being affected = 3/4

(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2

(b) The chance that the third child of Sara and James will be free of the condition = 3/4

(c)

(d) If someone has no family history of the disorder, their genotype would be AA.

AA x aa

4 Aa

The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history = 0

(e)

(f) The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history = 0

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2 years ago

Use the following information to answer Questions 18 through 20. Despite its name, the Pacific sea horse is actually a type of f

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20. Cell Membrane 19. Mitochondria 18. Osmosis

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In a two-point test cross, 36 of the offspring were recombinant types. The remaining 64 offspring were parental types. How many

Maksim231197 [3]

Answer:

Explanation:

A two-point test-cross is a cross between an individual with a double heterozygote genotype and a homo-zygous recessive individual in order to determine the recombination frequency between two linked genes. In genetics, one map unit (m.u.) can be defined as the measure of the distance (i.e., genetic distance instead of physical distance) between genes for which one (1) product of meiosis in one hundred (100) is recombinant. In this case, 36 of the offspring have the recombinant phenotype, while the remaining 64 offspring are not recombinant, and therefore both genes are separated by 36 mu (64 + 36 = 100 >> 36 mu).

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2 years ago