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coldgirl [10]
2 years ago
5

Stephen has a dog that weighs 5 times as much as lans dog. The total weight of both dogs is 72 pounds. How much does a Stevens d

og weigh
Mathematics
1 answer:
AlladinOne [14]2 years ago
4 0
X = Ian's dog
y = 5x
x + 5x = 72
6x = 72 
x = 12
We've found Ian's dog's weight, which is 12 pounds. However, the question asks us for Stephen's dog's weight, which is 12 times 5, giving us 60 pounds. Hope this helps!!!
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How is the graph of y = negative RootIndex 3 StartRoot x minus 4 EndRoot transformed to produce the graph of y = negative RootIn
SVEN [57.7K]

Answer:

Multiply by ∛2 and translate the graph to left by 4 units.

Step-by-step explanation:

The initial function given is:

y = -∛(x - 4)

The transformed function is:

y = -∛(2x - 4)

Consider the initial function.

y = -∛(x - 4)

(Represented by Black line in the graph)

Multiply the function by ∛2. The function becomes:

y = -∛(x - 4) × ∛2

y = -∛(2)(x-4)

y = -∛(2x-8)

(Represented by Red line in the graph represents this function)

Translate the graph 4 units to the left by adding 4 to the x component:

y = -∛(2x-8+4)

y= -∛(2x - 4)

(Represented by Blue line in the graph)

3 0
2 years ago
Read 2 more answers
A coat was originally priced at $50. It went on sale for $35. What was the percent that the cost was discounted?
Reptile [31]

Answer: 30 % Off

Step-by-step explanation:

8 0
2 years ago
Rammy has $9.60 to spend on some peaches and a gallon of milk. Peaches
sergeinik [125]

Answer:

\large \boxed{\text{5.00 lb}}

Step-by-step explanation:

\begin{array}{rcl}1.20x + 3.60 & \leq & 9.60\\1.20x & \leq & 6.00\\x &\leq & \mathbf{5.00}\\\end{array}\\\text{Rammy can buy $\large \boxed{\textbf{5.00 lb}}$ of peaches.}

Check:

\begin{array}{rcl}1.20(5.00) + 3.60 & \leq & 9.60\\6.00 + 3.60 & \leq & 9.60\\9.60 & \leq & 9.60\\\end{array}

OK.

5 0
2 years ago
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
LeAnn is purchasing giftwrap for a box that measures 8 inches long, 6 inches wide, and 6 inches tall. Calculate the total area o
Pavel [41]

Let

L---------> the length side of the box

W--------> the width side of the box

H-------> the height of the box

we know that

L=8\ in\\W=6\ in\\H=6\ in

the surface area of the box is equal to

S=2*area\ of\ the\ base+perimeter\ of\ the\ base*H

<u>Find the area of the base</u>

A=L*W=8*6=48\ in^{2}

<u>Find the perimeter of the base</u>

P=2*L+2*W=2*8+2*6=28\ in

<u>Find the surface area</u>

S=2*48+28*6

S=264\ in^{2}

therefore

<u>the answer is</u>

the total area of the box that will be covered in gift wrap is 264\ in^{2}

8 0
2 years ago
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