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xz_007 [3.2K]
2 years ago
4

Find the length of the hypotenuse of the right triangle MPQ, if tanM = and angle P is the right angle. 61 31 √61 √31

Mathematics
2 answers:
skelet666 [1.2K]2 years ago
5 0
In the question the value of tanM is missing but the value of tanM is equal to √6/5 in the question i found.
So,
tanM = √6/5 
<span>means MP=5 </span>
<span>PQ=</span>√<span>6 </span>
<span>hypotenuse by pyathagoras theorem =MQ=</span>√<span>6+25) </span><span>=</span>√<span>31

</span>Thus, the correct answer from the given options is √31.
Natasha2012 [34]2 years ago
3 0

Answer:

the square root of 31

Step-by-step explanation:

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A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr
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Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

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