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nikitadnepr [17]
1 year ago
8

The most likely result of completely removing carbon dioxide from the environment of a plant is that sugar production will

Biology
2 answers:
Trava [24]1 year ago
8 0
Sugar production would stop meaning the plant doesn't have the needed nutrient to make food for itself causing another factor : photosynthesis to stop aka the plant would die and wither
Elena L [17]1 year ago
7 0

<u>Answer</u>: Stop. No sugar production will take place.

<u>Explanation</u>:

  • The process by which plants make food is termed as photosynthesis . The sugar that is made by plants in this process is glucose.
  • For the process of photosynthesis <em>carbon</em> <em>dioxide</em> and water are converted to sugar and oxygen in the presence of sunlight.
  • Thus, we can see that there are 3 main components necessary for photosynthesis to take place:

1. Sunlight

2. water

3. carbon dioxide

Thus, if all the carbon dioxide is removed then the process of photosynthesis cannot proceed to produce glucose and hence <em>sugar production will stop</em>.

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Which two systems most directly interact in the fuzzy millipede's defense against ants?
Elanso [62]

Two systems most directly interact in the fuzzy millipede's defense against ants are :

<u>muscular and integumentary</u>

<u></u>

Explanation:

  • The fuzzy millipede, Polyxenus fasciculatus, is found in Texas and is preyed upon by most species of ants.
  • Most millipedes defend themselves with a variety of chemicals secreted from pores along the body, although the tiny bristle millipedes are covered with tufts of detachable bristles.
  • Due to their lack of speed and their inability to bite or sting, millipedes' primary defence mechanism is to curl into a tight coil – protecting their delicate legs inside an armoured exoskeleton.
  • Reproduction in most species is carried out by modified male legs called gonopods, which transfer packets of sperm to females.
  • Millipedes overwinter, so they may hide in cracks or crevices throughout the whole winter and emerge in the spring.
  • These insects live in dark, damp places and feed on decaying plant life, sometimes damaging crops. But they can serve a good purpose too.
  • To protect itself against the ants, it ejects fibers from a tuft located at the tail end of its body. When an ant attacks, the millipede flexes its back end toward the ant and wipes the tufts against it.

6 0
2 years ago
In a nucleotide, the nitrogenous base is attached to the sugar's _____ carbon and the phosphate group is attached to the sugar's
LUCKY_DIMON [66]

Answer:

A. 1' ... 5'

Explanation:

The pentose sugars present in nucleotides have five-carbon structures. Other components of a nucleotide are a phosphate group and a nitrogenous base. The nitrogenous base in a nucleotide can be a purine or pyrimidine. The purine bases are covalently joined to the 1' carbon atom of the pentose sugar at their N-9. The bond between the nitrogenous base and a pentose sugar is called the N-beta glycosyl bond.

Similarly, N-1 of a pyrimidine base is covalently linked to the 1' carbon of the pentose sugar. The phosphate group of a nucleotide is bonded to the 5' carbon of the pentose sugar.

8 0
1 year ago
PLEASE PLEASE PLEASE! Katie is researching the evolution of dinosaurs, which thrived during the Triassic, Jurassic, and Cretaceo
tresset_1 [31]

Answer: the graph supports: background extinctions, mass extinctions affected the evolution of mammals and dinosaurs

The graph does not support:both mammas and dinosaur revolved in the pattern of gradualism, dinosaurs evolved by adaptive radiation, and convolution affected the evolution of mammals and dinosaurs

Explanation:The graph only shows mass extinctions and background extinctions

3 0
1 year ago
How have the characteristics of each kind of cell put limitations and provided opportunities for the survival and divergence of
Nadusha1986 [10]
Water and carbon are major components of all life.Prokaryotic and eukaryotic are the two major categories of cells making up life on earth.
8 0
1 year ago
During each heartbeat, about 80 g of blood is pumped into the aorta in approximately 0.2 s. during this time, the blood is accel
aivan3 [116]
I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
                                   a = 1 m/s /  0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
                                  F = (80 g / 1000 g/kg) x (5 m/s²)
                                      = 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force. 
7 0
2 years ago
Read 2 more answers
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