Lost phosphorus is actually recycled through the processes of mineralization, reabsorption, dissolving, and precipitation.
Answer:the answer is B hope this help
Explanation:
The commence is off base with regards to the enthusiasm for creating fake blood. The intrigue is on the grounds that the timeframe of realistic usability of put away blood is extremely constrained. The other intrigue is concerning transfusion responses related with red platelet antigens that can bring about lethal responses and cause delays in finding good blood that hazard understanding lives. At present the rate of securing HIV disease through blood transfusions has been computed to associate with one case for every a million or two million transfusions. That viewpoint has been tackled with respect to testing however alternate issues still remain and they persuade the proceeded with look for simulated blood. Other developing infections like Zika and other obscure infections additionally makes a requirement for such research.
Answer:
c. Physical adaptations to the environment drive the distribution of all three species in the wild.
Explanation:
Options A and B refer to competition between species. The experiment was about the colonizing ability of the three species, and not the interaction among them. So these two options are not correct.
Option D states that species A is better adapted to the upper intertidal zone than the middle or lower. But the table shows that species A is equally adapted to colonize upper and middle intertidal zone, and less adapted to colonize lower zones.
The correct option is C. When these competing species coexist, this is because of niche partitioning or niche differentiation. If there is not any differentiation between them, the dominant species displaces the weak species. In the exposed example, the three species coexist in the middle and lower zones, which means that they probably have different niches and got adapted to living to their environments. This adaptation to different conditions is what leads to their distribution.
In the exposed example, species A and B can live in the upper intertidal zone, where species C can not live because they can not tolerate environmental conditions. The three species can live in the middle zone, but still, A and B are more adapted to this area than C. Among A and B, B is the most adapted to living in the upper and middle zones. Species C seems to be very adapted to live in the lower intertidal zone, where species A and B can also live, but are less adapted to this area, probably due to environmental conditions or due to their vulnerability to predation. In this last area, species A is less adapted.
According to given information,
Distance = 6 + 10 = 16 m
Displacement = 4 m
So, Distance - Displacement = 16 - 4 = 12 m
So, your final answer is 12 m.
Hope this helps!
