Answer:
The correct answer will be option- permits complementary base pairing
Explanation:
DNA contains four types of nitrogenous bases which pair with one another, identified by Erwin Chargaff.
Chargaff suggested that adenine binds thymine forming two hydrogen bonds and cytosine binds guanine forming three hydrogen bonds.
This base pairing between the complementary groups is known as a complementary base pairing which plays an important role in DNA.
The complementary base pairing allows the formation of the helical structure of DNA, the base pairs to be arranged in most energetically and favourable way and replication and transcription processes.
Thus, permits complementary base pairing is the correct answer.
Dr. Pringle suggests that there's only very few large herbivorous species that can survive in certain area. The reason behind his claim is that according to him there will be only enough food for few large species, so there's natural limitations in the food sources, as there should be enough to support them in order for them to survive.
On the other hand, in Mpala, there's 22 large herbivorous species, which directly contradicts Dr. Pringle's hypothesis. The reason why so many large species of herbivores an survive in Mpala and always have enough food for all of them, is that they have all specialized in eating certain types of plants or parts of plants, thus they are not direct competition to one another, and there's always enough food for all of them.
The basics would be that you'd need to find out if they could exchange genetic information. If not, they couldn't be considered part of one species. Set-up 2 artificial environments so both groups would produce pollen at the same time. Fertilise both plants with the other's pollen. Then fertilise the plants with pollen from their own group.
Count the number of offspring each plant produces.
If the plants which were fertilised by the opposite group produce offspring, they are of the same species. You can then take this further if they are of the same species by analysing if there is any difference between the number (and health) of offspring produced by the crossed progeny and by the pure progeny. You'd have to take into account that some of them would want to grow at different times, so a study of the progeny from their first sprout until death (whilst emulating the seasons in your ideal controlled environment). Their success could then be compared to that of the pure-bred individuals.
Make sure to repeat this a few times, or have a number of plants to make sure your results are accurate.
Or if you couldn't do the controlled environment thing, just keep some pollen one year and use it to fertilise the other group.
I'd also put a hypothesis in there somewhere too.
The independent variable would be the number of plants pollinated. The dependant variable would be the number of progeny (offspring) produced.
Domain (Specifically domain Eukarya)
<h2>Cytokinesis in animal cells</h2>
Explanation:
- The force for cytokinesis is generated by kinesin motors on microtubule bundles that form the contractile ring:This statement is false because cytokinesis in animal cells starts with the assembly of contractile ring,contractile band consists of actin and myosin(microfilaments) which catalyse cleavage furrow formation
- As the contractile ring constricts, its thickness increases to keep a constant volume:This statement is false because thickness remains constant
- The midbody forms from bundles of actin and myosin: This statement is false because contractile ring forms bundles of actin and myosin whereas midbody is formed from microtubules
- Local activation of Ran GTPase triggers the assembly and contraction of the contractile ring:This statement is false because local activation of Rho mediates profilin binding to actin and helps in assembly and contraction of contractile ring
The four letter string comes out to be FFFF