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irakobra [83]
2 years ago
14

Last week, Jason ran 26.1 miles. He wants to run further this week. He plans to run 2.4 miles to the park, four times around the

park, and 2.4 miles back from the park. To represent that inequality, he wrote: 2.4 + 4p + 2.4 ___ 26.1
Mathematics
2 answers:
son4ous [18]2 years ago
7 0

Answer:

Use the greater than symbol.

His goal does not include running exactly 26.1 miles; he needs to run more than 26.1 miles.

Equality should not be part of the solution set.

Step-by-step explanation:

its the sample answer, this is exactly what edge wants you to write

Leona [35]2 years ago
5 0

Question says that "Last week, Jason ran 26.1 miles. He wants to run further this week. He plans to run 2.4 miles to the park, four times around the park, and 2.4 miles back from the park. To represent that inequality, he wrote: 2.4 + 4p + 2.4 ___ 26.1"

We see a blank space before 26.1.

So we need to fill the suitable inequality symbol from <, >, ≤ and ≥.

In given expression "2.4 + 4p + 2.4 ___ 26.1", left side part "2.4 + 4p + 2.4", represents the total length of the path that Jason wants to cover this week.

He has decided to run more than 26.1 miles so that means the sum "2.4 + 4p + 2.4" must be greater than 26.1 miles.

Hence we will use > symbol so that left side becomes greater than the right side part.


So the final answer will be :

2.4 + 4p + 2.4 > 26.1

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Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack
brilliants [131]

Answer:

0.54 ounces in each tube

Step-by-step explanation:

Add the amount she used so we can add it in. 1.35+0.27= 1.62. Then divide it by the number of tube and since it was a 3 pack you divide it by 3. 1.62/3=0.54 so there is 0.54 ounces in each tube.

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If five friends want to share 1.25 of a pizza evenly how much pizza would each person get
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1.25 /5

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25/5 = 5

2 numbers

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Each person gets .25 of a pizza

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2 years ago
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Which of the following is the best definition of the domain
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Step-by-step explanation:

8 0
1 year ago
A meter is 3.37 inches more than a yard swimmer a swims 100 meters and swimmer b swims 100 yeards how many more feet did swimmer
olga_2 [115]
Swimmer a swims 100 meters, which is 100 1-meters, which is 100
(1 yards +3.37 inches) = 100 yards + 337 inches.

1 yard is 3 feet, so 100 yards are 300 feet.

100 in is 8.33 feet so
337 in is (337*8.33)/100=28.07 feet


Swimmer b swims 100 yards, which is 300 feet

Swimmer a swam 28.07 feet.


4 0
1 year ago
A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st
Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample credit hours per quarter = 15.2 credit hours

             s = sample standard deviation = 2.3 credit hours

             n = sample of students = 250

             \mu = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < t_2_4_9 < 1.96) = 0.95  {As the critical value of t at 249 degree of

                                        freedom are -1.96 & 1.96 with P = 2.5%}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{s}{\sqrt{n} } } , \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 15.2-1.96 \times {\frac{2.3}{\sqrt{250} } } , 15.2+1.96 \times {\frac{2.3}{\sqrt{250} } } ]

                  = [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0
1 year ago
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