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Troyanec [42]
2 years ago
14

Jessica is comparing her bank statement to her check register, and the ending balances don't seem to match. To check her registe

r for transposing errors, she needs to subtract the balances and _____ the difference _____.
Mathematics
2 answers:
uranmaximum [27]2 years ago
7 0

Answer:

Divide by 9

Step-by-step explanation:

Lina20 [59]2 years ago
6 0
<span>To balance her check register, Jessica needs to subtract the balances from her bank statement and then add the difference to the ending value of her check register. If entries in her bank statement do not appear in her check register, or vice versa, these transactions need to be tallied and then the added or subtracted from the ending balance in her check register.</span>
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If Patricia drives at two-third of her usual speed, she covers a certain distance in one hour more than the time she takes while
zalisa [80]
Let r = usual driving rate
let t = usual driving time
We need to figure out t

The distance she covers in her usual time at her usual rate is r*t

The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)

Set this equal to each other and solve for t.

rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2

So her usual time is 2 hours. (There's probably a faster way to do this)
3 0
2 years ago
Fill in missing information to make the equality true: <br> (... +2a)2 = … +12ab2+4a2.
BigorU [14]

Answer:

I suppose it should be

6b² and (6b²)²

or

6b² and 36b^{4}

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

therefore

(6b²+2a)² = (6b²)² + 12ab² + 4a²

3 0
2 years ago
Read 2 more answers
The function f(x) = 1/2 x + 3/2 is used to complete this table.
Mrac [35]

Answer:

a) f(-1/2)  = -2 is NOT TRUE.

b)  f(0)  =3/2 is  TRUE.

c)   f(1)  = -1 is NOT TRUE.

d)   f(2)  = 1 is NOT TRUE.

e)   f(4)  = 7/2  is  TRUE.

Step-by-step explanation:

Here, the given function is  f(x) = (\frac{1}{2}) x+\frac{3}{2}

Now, checking for each values for the given function:

a) Putting x  = (-1/2):

 f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2}   = \frac{-1}{4}  + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4}  = (\frac{5}{4} )

and (5/4) ≠  -2

Hence, f(-1/2)  = -2 is NOT TRUE.

b)Putting x  = 0 :

f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )

Hence, f(0)  =3/2 is  TRUE.

c) Putting x  = 1:

f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2}   = \frac{1}{2}  + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2}  = (\frac{4}{2} )   = 2\implies 2   \neq -1

Hence, f(1)  = -1 is NOT TRUE.

d)Putting x  = 2:  

f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2}   = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2}  = (\frac{5}{2} )

and (5/2) ≠  1

Hence, f(2)  = 1 is NOT TRUE.

e)Putting x  = 4:

 f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2}   = 2  + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2}  = (\frac{7}{2} )

Hence, f(4)  = 7/2  is  TRUE.

4 0
2 years ago
Which function is the inverse of f Superscript negative 1 Baseline (x) = negative one-half x minus three-halves?
aleksley [76]
I think the answer would be f-1(x)= 1/2x-3/2
4 0
2 years ago
Read 2 more answers
How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)
slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r  =   -2 • (r - 3s)

Equation at the end of step

 ((0-(9•(6s-4r)))+3s)--14•(r-3s)

Pulling out like terms

4.1     Pull out like factors :  6s - 4r  =   -2 • (2r - 3s)

Equation at the end of step

 ((0--18•(2r-3s))+3s)--14•(r-3s)

Final result :

 <u>50r - 93s</u>

7 0
2 years ago
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