Deanna is adjusting a satellite because she finds it is not focusing the incoming radio waves perfectly. The shape of her satell
ite can be modeled by x^2=12y where x and y are modeled in inches. She realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?
2 answers:
Answer:
The shape of satellite which is in the shape of parabola, opening upwards is, , having vertex (0,0).
Comparing with general equation of parabola
, having vertex (0,0) and focus (0,a).
Comparing the two above equation of parabola
4 a y = 12 y
4 a = 12
a=3
So, focus of the satellite which is in the shape of parabola=(0,3)
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Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
