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Alexxandr [17]
2 years ago
6

If the force of ventricular contraction increases, what will happen to the end-systolic volume?

Biology
1 answer:
Oduvanchick [21]2 years ago
7 0
I believe the end systolic volume would also increase...
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Compare and contrast polysaccharides and nucleic acids in terms of monomer diversity and how the monomers are joined together. D
NISA [10]

Monomers are the basic units of larger molecules-macromolecules. These units are connected via chemical bonds and when joined in repetition, a polymer is formed.

Monosaccharides (simple sugars) are monomers that form complex sugars-polysaccharides (long chains of monosaccharides usually form the energy-storing molecules found in food) by creating glycosidic bonds. Those linkages vary widely in geometry (can be linear and branched). Besides that, monosaccharides can have different functions in the organism and monomers vary extensively (in the orientations of hydroxyl groups and in location).

Monomers of nucleic acids (deoxyribonucleic acid-DNA and ribonucleic acid-RNA) are nucleotides composed of a five-carbon sugar, a phosphate, and a nitrogenous base. Monomers of nucleic acids do not vary that much, there are only four different monomers that include adenine and guanine, which are derived from purine; and cytosine and thymine (for DNA) or uracil (for RNA), derived from pyrimidine.

3 0
2 years ago
Read 2 more answers
In chickens, the allele for a pea comb (A) is dominant to the allele for a single comb (a). A mother with the genotype Aa and a
zloy xaker [14]

Answer:

The percent chance that the offspring will have a single comb is 25 %

Explanation:

Given,

The allele for single comb represented as "a" is recessive to the allele for pea comb represented as "A"

Genotype of male - Aa

Genotype of female - Aa

Gamete of Male - A, a

Gamete of female - A, a

Cross between Aa and Aa will produce

AA, Aa, Aa, aa

Thus, out of four offspring only one has "aa" genotype and hence this individual will express the recessive trait i,e  aa

The percent chance that the offspring will have a single comb is

\frac{1}{4} * 100\\

25 %

4 0
2 years ago
A student conducts a mark-recapture experiment to estimate the population size of sunfish in a small pond near her home. In the
jok3333 [9.3K]

Answer:

348.75 individuals, however you may need to round

Explanation:

To solve this problem, you need to think of the proportions you are given. Since she marked 45 fish in the beginning, and assuming none died, you can assume that there are 45 marked fish in the whole population. Therefore, when she takes the sample of 62 and sees that there are 8 marked fish, a good strategy is to take that proportion and use it to solve for the population like so:

8(marked fish in sample)/62(total in sample) = 45(total marked fish)/x(total population. Next cross-multiply 45 * 62 and 8 * x and set them equal to each other, getting you to the equation 2790 = 8x. Finally, to find x, the population size, divide 2790 by 8 to get x= 348.75.

5 0
2 years ago
32. As gradient increases, what happens to the<br> distance between isolines?
Annette [7]

Answer: Because the interval between isolines is constant, their spacing gives an visual indication of the change that occurs over a given distance, called a gradient. Hope this helps :)

Explanation:

3 0
2 years ago
For many generations, the following genotypic frequencies were observed in a large population of dinosaurs: 4 percent AA, 32 per
Usimov [2.4K]

Answer:

C) 19.7%

Explanation:

The new population distribution after climate change wiped out homozygous recessive dinosaurs is:

AA = \frac{4}{4+32}=\frac{1}{9}

Aa = \frac{32}{4+32}=\frac{8}{9}

The percentage of offspring of this new population that are homozygous recessive is given by:

P(Aa\ x\ Aa) = \frac{8}{9} *\frac{8}{9} =\frac{64}{81} \\P(aa) = \frac{1}{4}\\P(Aa\ x\ Aa) \cap P(aa) = \frac{64}{81}*\frac{1}{4} =0.197=19.7\%\\

19.7% of these newborn dinosaurs died

8 0
2 years ago
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