Answer: (A) Only differentiation is a process that results from stem cell division.
Explanation:
Cellular differentiation is the process by which a less specialized cell becomes a more specialized cell type. Differentiation occurs many times during the development of a multicellular organism. The organism changes from a single zygote to a complex system of tissues and cell types.
<span>According to the ipat model, technology that enhances our acquisition of minerals, fossil fuels, timber, and ocean fish increase environmental impact.
IPAT is a model or equation which expresses that
I (stands for Environmental impact) is the product of three factors: P (stands for population), A (is affluence) and T ( for Technology).
IPAT can be written as (I=PAT) or I = pxAxT</span>
Answer:
The correct answer is "The frequency of the B allele increased due to the selective pressures of the environment".
Explanation:
The missing part of the question is "Which of the following could best explain the increase in the frequency of the B allele in the population after five years?" at which the answer is "The frequency of the B allele increased due to the selective pressures of the environment".
In this study, the allelic frequency for black fur (B) in eastern gray squirrels Sciurus carolinensis changed from B=0.4 to B=0.6 within a lapse of five years. This increase is explained by the effect of selective pressures of the environment. For instance, is likely that new predators were more likely to detect squirrels with gray fur over black fur, or changes in the landscape benefited the black fur squirrels camouflage.
D-As stress levels increase, job efficiency increases is the correct answer.
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
