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Dafna11 [192]
2 years ago
10

In eastern gray squirrels, Sciurus carolinensis, the allele for black fur (B) is dominant to the allele for gray fur (b). In a p

articular population of gray squirrels, 64% have black fur and 36% have gray fur. A researcher calculated the allelic frequencies to be B=0.4 and b=0.6. Five years later, the researcher returned to the location and determined the allelic frequencies within the squirrel population to be B=0.6 and b=0.4
Biology
1 answer:
anastassius [24]2 years ago
5 0

Answer:

The correct answer is "The frequency of the B allele increased due to the selective pressures of the environment".

Explanation:

The missing part of the question is "Which of the following could best explain the increase in the frequency of the B allele in the population after five years?" at which the answer is "The frequency of the B allele increased due to the selective pressures of the environment".

In this study, the allelic frequency for black fur (B) in eastern gray squirrels Sciurus carolinensis changed from B=0.4 to B=0.6 within a lapse of five years. This increase is explained by the effect of selective pressures of the environment. For instance, is likely that new predators were more likely to detect squirrels with gray fur over black fur, or changes in the landscape benefited the black fur squirrels camouflage.

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A human RBC is approximately 6 µm in diameter. An unknown bacterium measures 1 ocular space using the oil immersion objective co
butalik [34]

Answer:

The following is the formula to determine the size from minor spaces and ocular spaces on the stage micrometer:  

Size = Number of minor spaces * 10 micrometer / Number of ocular spaces

A = Number of minor spaces is 2 and the number of ocular space is 1,

Size = 2 * 10 / 1 = 20 micro micrometer. Thus, the size of a bacterium is 20 micrometers.  

B = Thus, it can be said that the size of the bacterium is almost 4 times bigger in comparison to a human red blood cell, which is 6 micrometers in diameter.  

5 0
2 years ago
please help :) good morning :) For which of these questions could a testable hypothesis be developed? Check all that apply. Do c
Olin [163]

Answer:

peace be upon you dear

Explanation:

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8 0
2 years ago
Which of the following phenomena is a consequence of Independent Assortment? 1. Pure breeding plants, when mated with each other
Natalka [10]

Answer: The answer is that the phenotypic ratio among phenotypes produced from an F1 X F1 dihybrid cross is 9:3:3:1.

Explanation:

Independent assortment of genes explains how alleles on different chromosomes arrange independently of one another during gamete formation.

So, a dihybrid cross involving TWO characters (e.g Seed color & seed shape) would have its respective alleles DISTRIBUTED whether dominant or recessive, for crossing to occur and yield varying proportion of offspring in the well spread ratio of 9:3:3:1; making it a consequence of independent assortment of genes

7 0
2 years ago
Barium metal has a body-centered cubic lattice with all atoms at lattice points; its density is 3.51 g/cm3. From these data and
stiks02 [169]

Answer:

The unit cell's edge length is 5.06\times 10^{-8} m

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of barium metal= 3.51g/cm^3

Edge length of cubic unit cell= a  = ?

Atomic mass of Ba(M) = 137.33 g/mol

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

= density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

3.51 g/cm3=\frac{2\times 137.33g/mol}{6.022\times 10^{23} mol^{-1}\times (a)^{3}}

a = 5.06\times 10^{-8} m

The unit cell's edge length is 5.06\times 10^{-8} m

7 0
2 years ago
Name six types of cells that form during Morphogenesis of a horse
zepelin [54]
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Secretory cells- Glands (Sweat) 
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Muscle cells- Form muscles (body and organs) 
Reproductive cells- Allow for reproduction or furthering of the species
4 0
2 years ago
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