Transcript of EXCRETORY SYSTEM OF THE FROG AND HUMANTHE URINARY SYSTEM IS RESPONSIBLE FOR THE ELIMINATION OF WASTS VIA THE URINE. THE BASIC UNIT OF FUNCTION IS THE NEPHRON COMPOSED OF THE GLOMERULUS AND A SERIES OF TUBULES RESPONSIBLE FOR THE EXCRETION OF WASTES, REABSORPTION OF VALUABLE SUBSTANCES, AND FILTRATION OF BLOOD.
URINARY SYSTEM OF HUMAN
<span>EXCRETORY SYSTEM OF THE FROG AND HUMAN </span>
EACH KIDNEY CONTAINS UP TO 18 LOBULES AND THOSE 18 LOBES CONTAINS NEPHRONS ARE THE FUNCTIONAL UNIT OF THE KIDNEYS AND EACH KIDNEY CONTAINS MORE THAN 1 MILLION NEPHRONS. IN THE NEPHRONS COMPOSED OF GLOMERULUS FILTERS THE BLOOD LEAVING THE FILTRATE INSIDE THE GLOMERULAR SPACE. THE FILTRATE HAS SIMILAR CHARACTERISTICS TO PLASMA EPT IN THE PRESENCE OF PROTEINS IN THE FORM OF ALBUMIN. THE FILTRATE THEN GOES INTO THE PROXIMAL CONVOLUTED TUBULES WHERE MAJORITY OF THE SUBTANCES ARE REABSORBED.
KIDNEY
THE FLUID ENTERS THE DESCEDING LIMB OF HENLE WHERE IT IS IMPERMEABLE TO MINERALS AND OTHER SUBTANCES. THEREFORE, THE FLUID INSIDE THE TUBULES BECOMES HYPERTONIC COMPARED TO PLASMA. AS THE FLUID INSIDE GOES UP INTO THICK ASCENDING LIMB OF HENLE, WATER BECOMES IMPERMEABLE. THUS, IT IS ONE OF THE IMPORTANT DILUTING SEGMENTS OF THE URINARY SYSTEM. THERE IS ACTIVE TRANSPORT OF VARIOUS PHYSIOLOGICALLY IMPORTANT IONS SUCH AS POTASSIUM IONS, SODIUM IONS AND OTHERS.
URINARY SYSTEM OF THE FROG
EXCRETORY SYSTEM OF FEMALE FROG
EXCRETORY SYSTEM OF THE MALE FROG
LIQUID WASTE GENERATED BY THE KIDNEYS TRAVELS THROUGH THE MESONEPHRIC DUCT INTO E CLOACA. SOLID WASTE FROM THE LARGE INTESTINE PASSES INTO THE CLOACA. BOTH SOLID AND LIQUID WASTE MATERIALS LEAVE THE BODY THROUGH THE ANUS, THE ONLY OPENING FOUND IN THE POSTERIOR PART OF THE BODY.
THE FLUID THEN GOES INTO THE THIN ASCENDING LOOP OF HENLE AND INTO THE DISTAL CONVOLUTED TUBULE WHERE WATER AND SODIUM REABSORPTION IS EFFECTED BY ALDOSTERONE SECRETION BY THE ADRENAL CORTEX. THE FLUID THEN GOES IONTO COLLECTING TUBULES WHERE WATER REABSORPTION IS AFFECTED BY ADH.SOME REABSORPTION OF IMPORTANT IONS STILL OCCURS IN THESE FINAL SEGMENTS.
THE NEPRON
FINALLY, THE URINE DRAINS INTO THE MINOR AND MAJOR CALYX TO GO INTO THE RENAL PELVIS. FROM HERE IT IS DRAINED BY THE URETER TO BE TEMPORARILY STORED IN THE BLADDER WHERE PERIODIC EMPTYING OCCURS VIA THE URETHRA THROUGH THE PROCESS OF URINATION. THE URETHRA CONNECTS THE URINARY BLADDER TO THE GENITALS FOR THE REMOVAL OF URIE OUT OF THE BODY.
DIFFERENCES OF HUMAN AND FROG EXCRETORY
FROG
HUMAN
KIDNEY
KIDNEY
MESONEPHRIC DUCT
URETERS
URINARY BLADDER sorry caps
URETHRA
CLOACA
Answer:
Characteristics of epithelium tissue
1.Polarity- Epithelium is arranged so there is one free surface (apical surface) and one attached surface (basal surface)
2.Cellular nature– Cells in epithelium fit closely together side by side and sometimes atop each other to form sheets of cells. These sheets are held together by specialized junctions.
3.Supported by connective tissue– Attachment to a layer of connective tissue at the basal surface forms a layer called the basement membrane, an adhesive layer formed by secretions from the epithelial cells and the connective tissue cells.
4.Avascular– Epithelium typically lacks its own blood supply.
5.Regeneration– Epithelium cells can regenerate if proper nourished.
6.Absence of nerves (except for a few axons in the deeper layers)
Classification scheme of epithelial tissue:
Typically epithelial tissue is classified on the basis of arrangement and shape of cells. For naming the tissue types, the arrangement of the cells is stated first, then the shape, and is followed by “epithelium” to complete the naming. For example; Simple Squamous Epithelium.
Explanation:
Because the earth's axis is tilted. ... It is all about the tilt of the Earth's axis. Many people believe that the temperature changes because the Earth is closer to the sun in summer and farther from the sun in winter. In fact, the Earth is farthest from the sun in July and is closest to the sun in January!
D = m/v
Given:
D: .835 g/cm3
V: 34 cm3
M: ?
M= Dxv
M= .835 g/cm3 x 34 cm3
M= 28.39 g
Answer:
The unit cell's edge length is 
Explanation:
Number of atom in BCC unit cell = Z = 2
Density of barium metal= 
Edge length of cubic unit cell= a = ?
Atomic mass of Ba(M) = 137.33 g/mol
Formula used :
where,
= density
Z = number of atom in unit cell
M = atomic mass
= Avogadro's number
a = edge length of unit cell
On substituting all the given values , we will get the value of 'a'.
The unit cell's edge length is
