Question

The five members of the Traynor family each buy train tickets. During the train ride, each family member buys a boxed lunch for $6.50. If the total cost of the trip is $248.50, what is the price of each train ticket?

Answer 1

Let's assume

the price of each train ticket is x

we are given

total number of family members =5

so, total cost of ticket = total number of family members*the price of each ticket

so, total cost of ticket =5*x

so, total cost of ticket =5x

now, we have

each family member buys a boxed lunch for $6.50

so, total cost of lunch box = total number of family members*price of each lunch box

so, total cost of lunch box = 5*6.50

total cost of trip = total cost of ticket+total cost of lunch box

we are given

total cost of trip is $248.50

now, we can plug values

and we get

$248.50=5x+5*6.50$

now, we can solve for x

$248.50=5x+32.5$

$248.50-32.5=5x+32.5-32.5$

$216=5x$

$\frac{5x}{5} =\frac{216}{5}$

$x=43.2$

so,

the price of each train ticket is $43.2..........Answer

Answer 2

So 5(6.50) = 32.5
248.5 - 32.5 = 216
216/5 = 43.2
each ticket is $43.20