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Vlad [161]
2 years ago
9

Segment AB has endpoints A(–4, 6) and B(1, 4). After a dilation, centered at the origin, the image of A is (–6, 9). Without meas

uring the distance, explain how you could find the image of B
Mathematics
2 answers:
Tomtit [17]2 years ago
8 0
If the image is centered at the origin you can divide the terms of the image from the preimage to find the scale or ratio at which it was dilated. In this case, you will use the points of A because the point b does not matter in this case.

\frac{-6}{-4} = 1.5  and \frac{9}{6} = 1.5 so the image is dilated by a scale of 1.5

now that we know the scale we multiply the points of B by the scale to get the image.    1*1.5 = 1.5  and 4*1.5 = 6 so the image for B is (1.5, 6) 

choli [55]2 years ago
3 0

Answer:

To find the image of B, first find the scale factor for the dilation. The scale factor should be greater than 1 because the image of A is farther from the origin than A. Divide the coordinates of the image of A by the coordinates of A: –6/–4 = 3/2 and 9/6 = 3/2, so the scale factor is 3/2. Now, apply the dilation to B by multiplying the coordinates by 3/2 to get ((3/2)(1), (3/2)(4)), or (3/2, 6).



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Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name
sattari [20]

Answer:

Given: A triangle ABC and a line DE parallel to BC.

To prove: A line parallel to one side of a triangle divides the other two sides proportionally.

Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have

∠A=∠A (Common)

∠ADE=∠ABC (Corresponding angles)

Thus, by AA similarity, ΔABC is similar to ΔADE, therefore

AB/AD= AC/AE

⇒AD+DB/AD = AE+EC/AE

⇒1+DB/AD = 1+ EC/AE

⇒DB/AD = EC/AE

Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.

⇒Therefore Proved

Hope this helps!!!

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2 years ago
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Inga [223]

Answer:

This is late, but for anyone else that needs it, it's B. 4x-5

8 0
2 years ago
Read 2 more answers
Write the polynomial of least degree with roots -2, 5, and 7.
fomenos
For roots of -2, 5, and 7.

x = -2, x = 5, and x = 7

x = -2                        x = 5                             x = 7           

(x + 2) = 0                 (x - 5) = 0                   (x - 7) = 0

The polynomial of least degree would be:
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(x -2)(x -5) = x(x - 5) - 2(x -5)
              
                 = x² - 5x - 2x + 10

                 = x² - 7x + 10

 (x² - 7x + 10)(x -7)

x(x² - 7x + 10) - 7(x² - 7x + 10)

x³ - 7x² + 10x - 7x² + 49x - 70

x³ - 7x² - 7x² + 10x + 49x - 70

x³ - 14x² + 59x - 70

The least is   x³ - 14x² + 59x - 70
3 0
2 years ago
Describe how you regroup when you find the sum of 64+43
damaskus [11]
Here, regrouping is basically carrying. 

64+43 shown vertically would be:

  64
+43
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4+3 is 7, so seven is in the ones place, but that's not the point.
60+40 is 100, so you regroup by carrying the one to the hundreds place.

Hope I helped!

5 0
2 years ago
Consider the function represented be the table. What is f(0)?
mamaluj [8]

9514 1404 393

Answer:

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Step-by-step explanation:

The value of f(x) for x=0 is f(0). The first line of the table tells you that value is 6.

  f(0) = 6

7 0
2 years ago
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