In pea plants, yellow seed color is dominant and green seed color is recessive. What will the generations look like? Assume that
Mendel’s method of crossing two true breeding parents with opposite traits is followed. Check all that apply.
The P generation has all yellow seeds.
The P generation has all green seeds.
The P generation has yellow and green seeds.
The F1 generation has yellow and green seeds.
The F1 generation has all yellow seeds.
The F2 generation has all green seeds.
The F2 generation has yellow and green seeds.
The P generation has all yellow seeds.
The P generation has all green seeds.
The P generation has yellow and green seeds.
The F1 generation has yellow and green seeds.
The F1 generation has all yellow seeds.
The F2 generation has all green seeds.
The F2 generation has yellow and green seeds.
2 answers:
Answer:
The correct statements are:
- The P generation has yellow and green seeds.
- The F1 generation has all yellow seeds.
- The F2 generation has yellow and green seeds.
The given cross is the monohybrid cross between the plant with yellow seeds and plant with green seed.
Thus, the parent generation contains both yellow and green seed plants.
Let Y and y be the alleles of the gene responsible for seed color. Y is the dominant trait which codes for yellow color and y is the recessive allele which codes for green color.
The genotype of one parent is YY and that of another would be yy.
The cross would produce the offspring with genotype Yy. Thus, all the offspring would have yellow color seeds as yellow is the dominant trait.
On selfing F₁ generation, the offspring would produce with three types of genotypes YY, Yy, and yy in the ratio 1:2:1.
Thus, F₂ generation would contain yellow and green seeds in 3:1.
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