<span>In order to find the value of "a" and "b", first of all perform the multiplication in the parenthesis.
Thus
(3.5x1016) = 3556
and
(2.2x1010) = 2222
As per question;
(3556)x(2222) = 10 axb
By dividing both sides by "10"
we get
(3556)x(222.2) = axb
or
(355.6)x(2222) = axb
by comparing both sides of the equation,
we get that a = 3556 and b = 222.2
or
a = 355.6 and b = 2222
</span>
Answer:
The paramecium body.
Explanation:
1. The objective lenses on a compound light microscope doess have powers that start of as smallest to highest power, 4x, 10x, and 40x on the maximum power setting. This means that the sample can be magnified either, 40x, 100x or 400x.
At 40x magnification Stella will see organism 5mm.
At 100x magnification Stella will be able to see organism 2mm.
At 400x magnification Stella will be able to see organism more closely, 0.45mm, or 450 microns.
2. Paramecia are shoe shape or molded and almost transparent and shrouded in a defensive pellicle.
Pellicle capacities like skin and shields them from the components. For movement they have cilia.
The contents that a data in the food label is supported are
by having nutritional facts, example having the percent of carbohydrates
consumed in the food. Another thing, they often gave advice in milligrams when
having to label the nutritional fact such as having 1,300mg of calcium.
Answer:
All cells contain genetic information in the form of DNA molecules. ... Empirical evidence is required to differentiate between cause and correlation and to make claims about the role of DNA and chromosomes in coding the instructions for the characteristic traits passed from parents to offspring.
Explanation:
The answer is 49.92%
Let's use the <span>Hardy-Weinberg principle:
p + q = 1
p</span>² + 2pq + q² = 1
<span>
where:
p - the frequency of dominant allele G
q - </span>the frequency of recessive allele g
p² - the frequency of homozygous dominant individuals GG with colour green
2pq - the frequency of heterozygous individuals Gg with colour green
p² - the frequency of homozygous recessive individuals gg with color brown
23% of the population is brown: p² = 23% = 0.23
p = √(p²) = √0.23 = 0.48
p = 0.48
p + q = 1
0.48 + q = 1
q = 1 - 0.48 = 0.52
<span>The percentage of the population that is expected to be heterozygous is 2pq:
2pq = 2 * p * q = 2 * 0.48 * 0.52 = 0.4992 = 49.92%</span>
