Ben has 1/2 of a loaf of bread if he and his 3 friends share the 1/2 loaf equally how much of the whole loaf does each person ge
2 answers:
You might be interested in
Given:
Temperature at 10:00 am = 8 degrees Fahrenheit
Temperature drops by 3 degrees Fahrenheit every hour.
To find:
The temperature by 2:00pm of the same day.
Solution:
Let y be the temperature after x hour after 10:00 am.
The temperature at 10:00 am is the initial temperature.
So, y-intercept of the linear function is 8.
Temperature drops by 3 degrees Fahrenheit every hour.
So, slope of linear function is -3. Here, negative sign represents the decrease in the temperature.
Slope intercept form of a linear function is
where, m is slope and b is y-intercept.
Substitute m=-3 and y=8 in the above equation.
Difference between 2:00pm and 10:00 am is 4 hours. So, substitute x=4 in the above equation.
Therefore, the temperature by 2:00pm of the same day is -4 degrees Fahrenheit.
Answer:
52.56% probability that eight or more of the flights will arrive on time.
Step-by-step explanation:
For each flight, there are only two possible outcomes. Either it is on time, or it is not. The probability of a flight being on time is independent from other flights. So we use the binomial probability distribution to solve this question.]
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
At a certain airport, 75% of the flights arrive on time.
This means that
A sample of 10 flights is studied.
This means that
Find the probability that eight or more of the flights will arrive on time.
In which
52.56% probability that eight or more of the flights will arrive on time.
Diagram for part A and part C is attached herewith.
Solving for part B:-
Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that it bisects AC into two equal parts AB and BC. Now we have two triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property), and BA=BC (given in the question). Using SSS congruency of triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude ∡OBA=∡OBC (=90°). Hence OB⊥AC i.e. OB is perpendicular to AC.
Solving for part D:-
Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that AB is perpendicular to AC i.e. ∡B=90°. Now we have two Right triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property). Using HL congruency of right triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude BA=BC. Hence OB bisects AC into AB=BC.
