Question

Betty picks 4 random marbles from the bowl containing 3 white, 4 yellow, and 5 blue marbles

Answer 1

Answer:

0.0884

Step-by-step explanation:

Given that Betty picks 4 random marbles from the bowl containing 3 white, 4 yellow, and 5 blue marbles.

Prob that exactly 1 of the 4 marbles drawn is blue is

= Prob one ball blue and others non blue

= Prob one ball from 5 blue and 3 others from 7 non blue

= $\frac{5C1*7C3}{12C4} \\=0.0884$

Answer is 0.0884

Answer 2

There are 12 marbles in total in the bowl.
From this bowl, we will choose 4 marbles at random.
That's 12C4 or (12*11*10*9) or 11,880 ways

Out of this, what is the probability that there is exactly 1 blue marble.
There are 5 blue balls but only 1 is selected, 5C1 ways
The rest except blue calls are 7, but only 3 slots are left, 7C3 ways

The probably of exactly 1 blue of 4 marbles is then 5C1*7C3/12C4 = 1050/11,880 = 0.0884 or 8.84%

Hope this helps:) would appericate brainliest thanks