See tha attached pdf file and let me know how useful this answer is.
• The ball is at the same height as the building between 8 and 10 seconds after it is thrown. TRUE - the height is zero somewhere in that interval, hence the ball is the same height from which it was thrown, the height of the roof of the building.
• The height of the ball decreases and then increases. FALSE - at t=2, the height is greater than at t=0.
• The ball reaches its maximum height about 4 seconds after it is thrown. TRUE - the largest number in the table corresponds to t=4.
• The ball hits the ground between 8 and 10 seconds after it is thrown. FALSE - see statement 1.
• The height of the building is 81.6 meters. FALSE - the maximum height above the building is 81.6 meters. Since the ball continues its travel to a distance 225.6 meters below the roof of the building, the building is at least that high.
1. TRUE
2. False
3. TRUE
4. False
5. False
I hope choices must be given in the problem.
I am showing the method to find the equivalent equation of the above equation. You can match with your given choices.
First step is to expand the first term. So,
(x-4)² = (x - 4)(x - 4) Since a²= a*a
= x² - 4x - 4x + 4 * 4 By multiplying.
= x² -8x + 16 Combine the like terms.
So, (x - 4)² - (x -4) - 6
= x² - 8x + 16 - x + 4 - 6
= x² - 9x + 14 Combine the like terms.
So, equivalent equation of the above equation is x² - 9x + 14 = 0.
Answer:
Step-by-step explanation:
We are given that
Function f decreases from quadrant 2 to quadrant 1 and approaches y=0
It cut the y- axis at (0,6) and passing through the point (1,2).
Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.
It passing through the point (-1,2) and cut the y-axis at point (0,6).
Reflection across y- axis:
Rule of transformation is given by
Using the rule then we get
By using
Substitute x=-1
Substitute x=0
Therefore, is true.
