Answer:
A. $3992.50
Step-by-step explanation:
Credit line - $8,000.00
Summary
- Previous Balance Payments - $2,500.00
- Credits - $1,500.00
- New Purchases - $3,000.00
- Finance Charge - $7.50
- New Balance - $4,007.50
Available credit= credit line - new balance = $8000 - $4007.50= $3992.50
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 ) : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
x (Mean) - 2 s and x + 2 s
No
Step-by-step explanation:
she lives 10 miles away and the pizzeria only has a 6 mile radius.
Answer:
A. factor 4
Step-by-step explanation:
Just choose any side of the original one e.g 60mm and divide it by the lenght of the same side of the new one. In A. this gives you 60mm/15mm = 4. Then you can multiply the other lengths with that factor and if the result is equal to the sides of your original one you found the solution.
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.
