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nignag [31]
2 years ago
9

A group of men and women were given a maze puzzle. The time it took each person to solve the puzzle is recorded in the table. Co

mpletion Time for Men (seconds) Completion Time for Women (seconds) 285 285 120 335 185 251 76 88 172 131 220 54 147 217 277 94 285 270 337 94 75 77 160 178 140 180 257 223 264 177 204 112 80 230 121 188 79 108 364 119 256 205 94 88 97 180 125 103 85 122 176 337 136 The sample size of men is , and the sample size of women is . The mean time taken by to solve the puzzle is less than that taken by . NextReset
Mathematics
2 answers:
vichka [17]2 years ago
8 0

Answer:

The sample size of men is 19 , and the sample size of women is 34. The mean time taken by  men to solve the puzzle is less than that taken by women .

Step-by-step explanation:

levacccp [35]2 years ago
3 0

The Answer Is

<u><em>The sample size of men is 19 , and the sample size of women is 34 The mean time taken by Women to solve the puzzle is less than that taken by Men</em></u>


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Find the value of sin100.sin120.sin140.sin160​
NARA [144]

The value of sin100.sin120.sin140.sin160 is 0.1875

Step-by-step explanation:

To find the value of sin100.sin120.sin140.sin160, let us find the value of each angle.

The value of sin100=0.9848

The value of sin120=\frac{\sqrt{3} }{2}

The value of sin140=0.6428

The value of sin160=0.3420

Substituting the values of sin, we get,

sin100.sin120.sin140.sin160=0.9848*\frac{\sqrt{3} }{2} *0.6428*0.3420

Multiplying the values of sin, we get,

sin100.sin120.sin140.sin160=0.1875

Thus, the value of sin100.sin120.sin140.sin160 is 0.1875

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2 years ago
A stock has produced returns of 11.9 percent, 5.6 percent, 16.4 percent, and -4.2 percent over the past four years, respectively
EleoNora [17]

The average annual return is

\displaystyle ((1+0.119)(1+0.056)(1+01.64)(1-0.042))^{\frac{1}{4}}-1=\sqrt[4]{1.317687706368}-1\\\\ \approx 7.14\%

8 0
2 years ago
For what values of m does the graph of y = 3x^2 + 7x + m have two x-intercepts? a) m&gt;12/49 b) m&lt;12/49 c) m&lt;49/12 d) m&g
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The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

<span>Δ=<span>b2</span>−4ac</span> Whenever we solve a quadratic equation that is complete and we analyze the discriminant, we can get 3 scenarios: <span>if→Δ>0<span>=></span>∃<span>x1</span>,<span>x2</span>/a<span>x2</span>+bx+c=0</span> This just means: "if the discriminant is greater than zero, there will exist two x-intercepts" And for the second scenario: <span>if→Δ=0→∃<span>xo</span>/a<span>x2</span>+bx+c=0</span> This means: "if the discriminant is equal to zero, there will be one and only one x-intercept" And for the last scenario: <span>if→Δ<0→∃x∉R/a<span>x2</span>+bx+c=0</span> This means that :"if the discriminant is less than zero, there will be no x-intercepts" So, if we take your excercise and analyze the the discriminant: <span>3<span>x2</span>+7x+m=y</span> we will find the values that satisfy y=0 : <span>3<span>x2</span>+7x+m=0</span> And we'll analyze the discriminant: <span>Δ=<span>72</span>−4(3)(m)</span> And we are only interested in the values that make the discriminant equal zero: <span><span>72</span>−4(3)(m)=0</span> All you have to do is solve for "m".

6 0
2 years ago
The heights of students at a college are normally distributed with a mean of 175 cm and a standard deviation of 6 cm. One might
frosja888 [35]

Answer:

25

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 175cm

Standard deviation = 6 cm

Percentage of students below 163 cm

163 = 175 - 2*6

So 163 is two standard deviations below the mean.

By the Empirical rule, 95% of the heights are within 2 standard deviations of the mean. The other 100-95 = 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of them are more than 2 standard deviations below the mean(so below 163cm) and 2.5% are more than two standard deviations above the mean.

2.5% of the students have heights less than 163cm.

Out of 1000

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25 is the answer

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Answer:

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