Question

In a population of 100 four-o'clock flowers there are 40 red-flowered plants (crcr), 38 pink-flowered plants (crcw), and 22 white-flowered plants (cwcw) what is the frequency of the cw allele in this population

Answer 1

0.41 or 41%..............is the CW frequency.


Apply Hardy - Weinberg Equilibrium for two Genes.
( CW and CR); according to p^2 + q^2 + 2pq = 1

p^2 = 40, p = 0.447
q^2 = 22, q = 0.413 Frequency of allele 0.41




Total Population = 100
Red Flowers = 40 
frequency = 40/100 = 0.4


Pink flowers = 38
frequency = 38/100 = 0.38


white flower = 22
frequency = 22/100 = 0.22


Let:    C^rC^r Red flower = p^2
          C^rC^w Pink flower = 2pq
          C^wC^w   White flower = q^2


Use Hardy Weinberg principle  p^2 + q^2 = 2pq = 1

Frequency of CW allele = 1/2(2pq) + q^2

Divide the 2pq by 2 because, needed to account only for C^w and not the partner C^r.



So, 1/2(0.38) + 0.22 = 0.41 or 41% answer.




Hope this helps!!!!

Answer 2

Answer:

0.41

Explanation:

In a population of 100 four-o'clock flowers there are 40 red-flowered plants (crcr), 38 pink-flowered plants (crcw), and 22 white-flowered plants (cwcw) what is the frequency of the cw allele in this population

four-o'clock flower has two alleles for each gene. making 2*100=200

The white flowered plants have two copies of CW alleles, making 2*22=44

The pink flowered plants have one each, making 1*38

To get the probability or the frequency of occurrence, we simply find

the frequency of the cw allele in this population=

Total number of white flowered plants x two+Total numbered of pink flowered plants*1/(The total population*2)

22*2+38*1/(100*2)

82/200

0.41