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rusak2 [61]
2 years ago
8

In a right triangle, angle A measures 20°. The side opposite angle A is 10 centimeters long. Approximately how long is the hypot

enuse of the triangle? 3.4 centimeters 10.6 centimeters 27.5 centimeters 29.2 centimeters
Mathematics
2 answers:
kobusy [5.1K]2 years ago
6 0

Answer:

D, 29.2 centimeters

lubasha [3.4K]2 years ago
3 0
Given that the angle measure 20 and the side opposite to that angle measures 10 cm, suppose this is the height of the triangle, the hypotenuse
Such that
sin theta=opposite/hypotenuse
opposite=a=10 cm
sin 20=10/h
multiplying both sides by h we get
hsin20=10
hence;
h=10/sin20
h=29.24 cm
h=29.2 cm 

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1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
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You and your friend are selling tickets to a charity event. You sell 11 adult tickets and 8 student tickets for $158. Your frien
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If ΔMNO ≅ ΔXYZ, then what corresponding parts are congruent?
8090 [49]

Answer:

∠N and ∠Y

Step-by-step explanation:

When two triangles are congruent then there corresponding parts ( angle or sides ) are also congruent or equal, ( CPCTC )

In triangles MNO and XYZ,

Side MN, NO and OM are corresponding to XY, YZ and ZX respectively,

And, angles M, N and O are corresponding to angles X, Y and Z respectively,

Thus, if ΔMNO ≅ ΔXYZ

By CPCTC,

MN ≅ XY

NO ≅ YZ

OM ≅ ZX

Also, ∠M ≅ ∠X, ∠N ≅ ∠Y and ∠O ≅ ∠Z

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Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y
lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

  1. Translate one of the two circles so that they have the same center
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Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

  1. Start with circle X and radius r
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  3. Scale the radius of circle X' until it becomes s. This new circle, say X'', is similar to X' because you only scaled it

So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

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A pair of boots marked for $25 was sold at $15. What was the
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Answer:

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