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zimovet [89]
2 years ago
9

Ricardo throws a stone off a bridge into a river below. The stone's height (in meters above the water), xxx seconds after Ricard

o threw it, is modeled by w(x)=-5(x-8)(x+4)w(x)=−5(x−8)(x+4)w, left parenthesis, x, right parenthesis, equals, minus, 5, left parenthesis, x, minus, 8, right parenthesis, left parenthesis, x, plus, 4, right parenthesis What is the maximum height that the stone will reach?
Mathematics
1 answer:
Dominik [7]2 years ago
7 0
For this case we have the following function:
 <span>w (x) = - 5 (x-8) (x + 4)
 </span><span>Rewriting we have:
 </span><span>w (x) = - 5 (x ^ 2 + 4x - 8x - 32)
 </span><span>w (x) = - 5x ^ 2 - 20x + 40x + 160
 </span><span>w (x) = - 5x ^ 2 + 20x + 160
 </span><span>Then, deriving we have:
 </span><span>w '(x) = - 10x + 20
 </span><span>We equal zero and clear x:
 </span><span>0 = -10x + 20
 </span><span>10x = 20
 </span><span>x = 20/10
 </span><span>x = 2 seconds
 </span><span>Substituting values:
 </span><span>w (2) = - 5 (2-8) (2 + 4)
 </span><span>w (2) = - 5 (-6) (6)
 </span><span>w (2) = 180 meters
 </span>Answer:
 
The maximum height that the stone will reach is:
 
w (2) = 180 meters
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Answer:

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Step-by-step explanation:

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= length of Arc BA  / Radius

= 8.4 / 8  = 1.05 radians = 60.16° ≈ 60°

<u>ii) what is the length of arc BAC</u>

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Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

\dfrac{sin \  F}{f} = \dfrac{sin  \ A }{a}

\dfrac{sIn \  79}{6} = \dfrac{sin \   63}{a}

a sin 79 = 6 sin 63

a =\dfrac{6 \times sin \ 63}{sin \ 79}

a =\dfrac{6 \times 0.8910}{0.9816}

a = 5.446 millas

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