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Anon25 [30]
2 years ago
9

14 jars, each with a capacity of 2.5 lb, are needed to hold a certain amount of honey. How many jars with a capacity of 3.5 lb w

ould be needed to hold the same amount of honey?
Mathematics
2 answers:
earnstyle [38]2 years ago
6 0

Answer:

10 jars of capacity 3.5 lb are needed to hold the same amount of honey.

Step-by-step explanation:

14 jars, each with a capacity of 2.5 lb, are needed to hold a certain amount of honey.

that means 14×2.5 jars of capacity 1 lb are needed to hold the same amount of honey

That means  \dfrac{14\times 2.5}{3.5} jars of capacity 3.5 lb are needed to hold the same amount of honey

i.e. 10 jars of capacity 3.5 lb are needed to hold the same amount of honey.

zmey [24]2 years ago
5 0
Multiply 14 by 2.5 to see how much honey is being held within all the jars (combined). We get 35. Now, all we need to do to find how many 3.5 lb jars we would need to hold 35 pounds of honey. Do this by dividing 35 by 3.5, which is equal to 10 jars (3.5 lb) to hold the same amount of honey.
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What new topics did Isaac Newton discover?
solong [7]
Newton's 3 Laws of Motion are probably the most recognized. 
His universal law Gravitation.
He paved the way for advances in Integral and Differential Calculus. 
5 0
2 years ago
Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b
horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
Which equation represents a line that passes through (5, 1) and has a slope of StartFraction one-half EndFraction?
saul85 [17]

Answer:

y – 1 = y minus 1 equals StartFraction one-half EndFraction left-parenthesis x minus 5 right-parenthesis.(x –5)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=\frac{1}{2}

(5,1)

substitute

y-1=\frac{1}{2}(x-5)

5 0
2 years ago
Read 2 more answers
Katherine is landscaping her home with juniper trees and pansies. She wants to arrange 15 pansies around each of 8 trees. Each t
Doss [256]
Let
X-----------------> number of pansies
y-----------------> number of trees

we know that
x=15*8----------> x=120 pansies
y=8 trees

cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12

[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)   

[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216

the answer is 
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

Katherine’s final cost is $216
5 0
2 years ago
Read 2 more answers
Matt can buy and 8 ounce jar of salsa for $2.79 or a 15 ounce jar of salsa for $5.54 which jar has the best unit rate
sasho [114]

Answer:

8 ounce jar

Step-by-step explanation:

We divide the price by the number of ounces to find the unit rate or cost per one ounce.

2.79/8=0.34875

5.54/15=0.3693

The 8 ounce jar has the best unit rate with a lower cost per ounce.

5 0
2 years ago
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