I believe it's C! (: Oysters!
Good luck, rockstar! I hope all is well, and you pass. (:
Answer:
0.2404
Explanation:
The genes R/r and E/e are linked and there is 4% recombination between them.
<u>The possible genotypes and phenotypes are:</u>
- RR or Rr: Rh+ blood type
- rr: Rh- blood type
- EE or Ee: elliptocytosis
- ee: normal red blood cells
Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).
Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele from his father, so he has the genotype eR/Er.
Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.
The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).
<u />
<u>Tom will produce the following gametes:</u>
- eR, parental (0.48)
- Er, parental (0.48)
- er, recombinant (0.02)
- ER (recombinant (0.02)
<u>Terri will produce the following gametes:</u>
- ER, parental (0.48)
- er, parental (0.48)
- Er, recombinant (0.02)
- eR, recombinant (0.02)
A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:
- Er (0.48) × er (0.48) = 0.2304 Er/er
- Er (0.48) × Er (0.02) = 0.0096 Er/Er
- er (0.02) × Er (0.02) = 0.0004 er/Er
And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404
Answer:
B. Birds allow their temperature drop in order to increase their production efficiency.
Explanation:
Most birds can drop the temperature a few centigrade degrees, while there are torpid birds capable of lowering much more. Birds can drop body temperature in response to environmental conditions. Bird species including, among others, swifts, hummingbirds and chickadees are capable of regulating body temperature during torpor state. There are different morphological and behavioral adaptative traits that enable birds to minimize the cost of thermoregulation. In the first place, epidermis surface allows heat loss to the environment, while arteries and veins in the legs help to retain heat in cold conditions.
Answer:
C) 128
Explanation:
In binary fission each bacterial cell will divide into two parts.
1. Since the bacteria divides divides after every 20 min , We have to find the number of division in two hours two hour(2x60=120 min) which will be;
120÷20=6
It will undergo 6 divisions.
2. To calculate the number of bacteria at the end of 2 hours
Bacteria in the beginning x 2∧ Number of division
1× 2∧6= 128 Bacteria
The correct answer is B. Pond
Oceans and lakes have huge diversity when it comes to temperature, while lagoons also have them except they're not as vast.
